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sineoko [7]
3 years ago
5

Which statement explains the polarity of a water molecule?

Physics
1 answer:
timofeeve [1]3 years ago
8 0

Answer:

D. The oxygen side is partially negative because electrons are pulled toward the oxygen side.

Explanation:

The water molecule is polar by the virtue of covalent bonds and the hydrogen bonds within and between its molecule.

The oxygen side is partially negative because the electrons are pulled toward the oxygen side.

Between oxygen and hydrogen that makes up the water molecule, oxygen is more electronegative.

An electronegative atom has more affinity for electrons. Since the electrons in the molecule of water is shared between hydrogen and oxygen, the more electronegative specie which is water draws the electron more to itself.

This leaves a net negative charge on the oxygen atom.

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Explanation:

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A 1,400 kg car accelerates from rest to 30 m/s in 6.0 seconds. what is the net force on the car?
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3 years ago
What is the relationship between frequency ad wavelenght
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Frequency and wavelength are inversely proportional to each other. The wave with the greatest frequency has the shortest wavelength. Twice the frequency means one-half the wavelength. For this reason, the wavelength ratio is the inverse of the frequency ratio.

7 0
3 years ago
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At the county fair, Chris throws a 0.12kg baseball at a 2.4kg wooden milk bottle, hoping to knock it off its stand and win a pri
viva [34]

Answer:

v_{f2} =6.5%v_{i1}

Explanation:

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Initial velocity of the ball:   v_{i1}

final velocity of the ball: v_{f1} which is -30/100 of v_{i1} =-0.3v_{i1}

Mass of the bottle: m_{2} =2.4kg

Initial velocity of the bottle: v_{i2}=0m/s

final velocity of the bottle: v_{f2} is unknown (to find)

<em>by using conservation momentum, which stated that the initial momentum is equal to the final momentum.</em>

<em />m_{1} v_{i1} +m_{2} v_{i2} =m_{1} v_{f1} +m_{2} v_{f2}<em />

<em>so since the bottle is at rest firstly, therefore </em>v_{i2} =0<em />

<em />m_{1} v_{i1} +m_{2} (0) =m_{1} v_{f1} +m_{2} v_{f2}<em />

<em />m_{1} v_{i1}  =m_{1} v_{f1} +m_{2} v_{f2}<em>         </em><em>equation 1</em>

so now substitute v_{f1} into equation 1

m_{1} v_{i1}  =m_{1} (-0.3v_{i1} ) +m_{2} v_{f2}

<em />m_{1} v_{i1}  = -0.3m_{1}v_{i1}  +m_{2} v_{f2}<em />

<em>collect the like terms</em>

m_{1} v_{i1}   +0.3m_{1}v_{i1}  =m_{2} v_{f2}

1.3m_{1} v_{i1}   =m_{2} v_{f2}

divide both  side by m_{2}

v_{f2}=\frac{1.3m_{1} v_{i1}}{m_{2} }

Now substitute

v_{f2} =\frac{1.3*0.12*v_{i1}}{2.4}\\v_{f2}    =\frac{0.156v_{i1} }{2.4} \\v_{f2} =0.065v_{i1}

v_{f2} =6.5%v_{i1}

<em />

6 0
3 years ago
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