10+18=28
17+11=28
OR
2x=28 where x=14
4x where x=7
Answer:
<h3>Hence required integers are 11 and 13</h3>
Let x an odd positive integer
Then, according to question
x^2 +(x+2)^2=290
2x^2 +4x−286=0
x^2 +2x−143=0
x ^2+13x−11x−143=0
(x+13)(x−11)=0
x=11 as x is positive
Hence required integers are 11 and 13
Step-by-step explanation:
Hope it is helpful....
2you suppose to multiplie the lenghts to the base
The correct answer is C (7, 9)
Firstly we know that each point is 6 away from the other in terms of x and in terms of y. Now we also know that for every 6, we will be one away from point B and five away from point A. We know this because the ratio is AB 5:1, meaning that the 5 is on the A side (they both come first).
So, we can just add 5 to each of the A value numbers to get point P.
A = (2, 4)
P = (2+5, 4+5)
P = (7, 9)