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Softa [21]
3 years ago
12

Rewrite as a simplified fraction: 2.67 (67 repeated) as a fraction. (i dont need the work)

Mathematics
2 answers:
Archy [21]3 years ago
6 0

Answer: 2 6/99

Step-by-step explanation:

Vaselesa [24]3 years ago
4 0

Answer:

2 67/99

Step-by-step explanation:

Hope this helps.

Please mark as Brainliest and give 5 stars.

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How many times larger is 4 x 10^8 than 2 x 10^-5
True [87]

Answer:The answer is 8x10^7

Step-by-step explanationi took the thing

7 0
3 years ago
Let the following sample of 8 observations be drawn from a normal population with unknown mean and standard deviation:
Vikentia [17]

Answer:

a

   \= x  = 18.5  ,  \sigma =  5.15

b

 15.505 < \mu <  21.495

c

 14.93 < \mu <  22.069

Step-by-step explanation:

From the question we are are told that

    The  sample data is  21, 14, 13, 24, 17, 22, 25, 12

     The sample size is  n  = 8

Generally the ample mean is evaluated as

        \= x  =  \frac{\sum x  }{n}

        \= x  =  \frac{  21 + 14 + 13 + 24 + 17 + 22+ 25 + 12  }{8}

         \= x  = 18.5

Generally the standard deviation is mathematically evaluated as

         \sigma =  \sqrt{\frac{\sum (x- \=x )^2}{n}}

\sigma =  \sqrt{\frac{\sum ((21 - 18.5)^2 + (14-18.5)^2+ (13-18.5)^2+ (24-18.5)^2+ (17-18.5)^2+ (22-18.5)^2+ (25-18.5)^2+ (12 -18.5)^2 )}{8}}

\sigma =  5.15

considering part b

Given that the confidence level is  90% then the significance level is evaluated as

         \alpha  =  100-90

         \alpha  = 10\%

         \alpha  = 0.10

Next we obtain the critical value of  \frac{ \alpha }{2}  from the normal distribution table the value is  

     Z_{\frac{ \alpha }{2} }  =  1.645

The margin of error is mathematically represented as

      E =  Z_{\frac{ \alpha }{2} } *  \frac{\sigma }{\sqrt{n} }

=>    E =1.645  *  \frac{5.15 }{\sqrt{8} }

=>     E =  2.995

The 90% confidence interval is evaluated as

       \= x  -  E < \mu <  \= x +  E

substituting values

       18.5 -  2.995 < \mu <  18.5 +  2.995

       15.505 < \mu <  21.495

considering part c

Given that the confidence level is  95% then the significance level is evaluated as

         \alpha  =  100-95

         \alpha  = 5\%

         \alpha  = 0.05

Next we obtain the critical value of  \frac{ \alpha }{2}  from the normal distribution table the value is  

     Z_{\frac{ \alpha }{2} }  =  1.96

The margin of error is mathematically represented as

      E =  Z_{\frac{ \alpha }{2} } *  \frac{\sigma }{\sqrt{n} }

=>    E =1.96  *  \frac{5.15 }{\sqrt{8} }

=>     E = 3.569

The 95% confidence interval is evaluated as

       \= x  -  E < \mu <  \= x +  E

substituting values

       18.5 - 3.569 < \mu <  18.5 +  3.569

       14.93 < \mu <  22.069

8 0
3 years ago
What is the gcf for 42n - 27s​
Trava [24]

Answer:

3

Step-by-step explanation:

5 0
3 years ago
If (a−8)/3=(a−3)/2 , then a = ?
Tresset [83]

Answer:

\frac{(a - 8)}{3}  =  \frac{(a - 3)}{2}  \\ 2(a - 8) = 3(a - 3) \\ 2a - 16 = 3a - 9 \\ 3a - 2a =  - 7 \\ a =  - 7

4 0
3 years ago
Read 2 more answers
Marty is spending money at the average rate of $3 per day. After 14 days he has $68 left.
slega [8]
A) 110 - (3 × 14x) = 68
B) 3×14 is 42 so he spent $42 in two weeks 42+68= 110 so he had $110 to begin with
C) he will run out of money in about 22 days (22.6666666667)
4 0
3 years ago
Read 2 more answers
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