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den301095 [7]
2 years ago
10

Definitions given.

Mathematics
1 answer:
Yuki888 [10]2 years ago
8 0

The pitch of the roof is given by the ratio of the rise to the run of the roof, which is the slope of the rafter

The \ pitch  \ of  \ the \  roof  \ is \ \mathbf {\dfrac{6}{13}}

Please find attached the simple <u>diagram of the house</u> with all measurements labeled

The reason the above value for the pitch and the diagram are correct are as follows:

The given parameters are;

Width of the section of the house on which the gable of the roof is to be placed = 50 feet

Length of the over hang on the sides of the roof = 1 foot each

Total span of the roof = 52 feet

Horizontal length of each rafter, the run = 26 feet

The height of the ridge above the top of the frame, the rise = 12 feet

Required:

  • To find the pitch of the roof
  • To draw a diagram of the house showing measurements

Solution:

Pitch = \dfrac{Rise}{Run}

  • Pitch  \ (slope) \ of \ roof =  \dfrac{12}{26} =\dfrac{6}{13}

Please find attached the <u>diagram</u> of the house showing the measurements for the roof parameters and the section of the house where the gable roof is to be placed

Learn more about finding the slope of a line here:

brainly.com/question/18990889

brainly.com/question/17105217

brainly.com/question/20987659

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Answer:

There are NO real roots for this equation. The only roots have imaginary parts and therefore cannot be represented on the real x-axis.

Step-by-step explanation:

We notice that the expression on the left of the equation is a quadratic with leading term 2x^2, which means that its graph is that of a parabola with branches going up.

Therefore, there can be three different situations:

1) if its vertex is ON the x axis, there would be one unique real solution (root) to the equation.

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3) if its vertex is above the x-axis, it will have NO real solutions (roots) but only non-real ones.

So we proceed to examine the vertex's location, which is also a great way to decide on which set of points to use in order to plot its graph efficiently.

We recall that the x-position of the vertex for a quadratic function of the form  f(x)=ax^2+bx+c is given by the expression:

x_v=\frac{-b}{2a}

Since in our case a=2 and b=-3, we get that the x-position of the vertex is:

x_v=\frac{-b}{2a}\\x_v=\frac{-(-3)}{2(2)}\\x_v=\frac{3}{4}

Now we can find the y-value of the vertex by evaluating this quadratic expression for x = 3/4:

y_v=f(\frac{3}{4})=2( \frac{3}{4})^2-3(\frac{3}{4})+4\\f(\frac{3}{4})=2( \frac{9}{16})-\frac{9}{4}+4\\f(\frac{3}{4})=\frac{9}{8}-\frac{9}{4}+4\\f(\frac{3}{4})=\frac{9}{8}-\frac{18}{8}+\frac{32}{8}\\f(\frac{3}{4})=\frac{23}{8}

This is a positive value for y, therefore we are in the situation where there is NO x-axis crossing of the parabola's graph, and therefore no real roots.

We can though estimate a few more points of the parabola's graph in order to complete the graph as requested in the problem. For such we select a couple of x-values to the right of the vertex, and a couple to the right so we can draw the branches. For example: x = 1, and x = 2 to the right; and x = 0 and x = -1 to the left of the vertex:

f(-1) = 2(-1)^2-3(-1)+4= 2+3+4=9\\f(0)=2(0)^2-3(0)+4=0+0+4=4\\f(1)=2(1)^2-3(-1)+4=2-3+4=3\\f(2)=2(2)^2-3(2)+4=8-6+4=6

See the graph produced in the attached image.

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X=5+(1.282)(0.1)=5.1282

Therefore, the 90th percentile weight is 5.1282 pounds.

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X=5+(-1.282)(0.1)=4.8718

The difference between these two weights is 5.1282-4.8718=\boxed{0.2564\text{ pounds}}.

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