Changes in the forms of energy are called
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The molarity of a Sodium carbonate solution : 0.373 M
<h3>Further explanation</h3>Given
32.52 g Na₂CO₃
822 ml of solution = 0.822 L
Required
The molarity
Solution
Molarity shows the number of moles of solute in every 1 liter of solution.
mol of solute = mol of Na₂CO₃ :
= mass : MW Na₂CO₃
= 32.52 g : 106 g/mol
= 0.307
Molarity :
= n : V
= 0.307 mol : 0.822 L
= 0.373 M
Answer:
a. Here, the yellow precipitate is lead (II) iodide:
b. Here the white precipitate is barium sulfate:
c. Here the brown precipitate is iron (III) hydroxide:
d. Here, the precipitate is copper (II) hydroxide:
Explanation:
Hello.
In this case, since the precipitation reactions are characterized by the formation of a product which is highly insoluble in water, specially very heavy products having heavy metals at the cations, for each case we proceed as follows:
a. Here, the yellow precipitate is lead (II) iodide:
b. Here the white precipitate is barium sulfate:
c. Here the brown precipitate is iron (III) hydroxide:
d. Here, the precipitate is copper (II) hydroxide:
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