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3 years ago

6

What would happen to the moon’s interia were to increase? A the moon will fly into space. B the moon will smash into Earth. C th

e moon will smash into pluto.

1 answer:

Montano1993 [528]3 years ago

5 0

Answer:

B

Explanation:

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For the reaction Ti(s)+2F2(g)→TiF4(s) compute the theoretical yield of the product (in grams) for each of the following initial

Ostrovityanka [42]

Answer:

The answer to your question is 8.2 g of TiF₄

Explanation:

Data

Theoretical yield = ?

mass of Ti = 5 g

mass of F₂ = 5 g

Balanced chemical reaction

Ti(s) + 2F₂ (g) ⇒ TiF₄(g)

Process

1.- Calculate the Molar mass of reactants and products

Ti = 48 g

2F₂ = 2( 19 x 2) = 76 g

TiF₄ = 48 + 76 = 124 g

2.- Calculate the limiting reactant

theoretical proportion Ti/F₂ = 48/76 = 0.63

experimental proportion Ti/F₂ = 5/5 = 1

Conclusion The limiting reactant is F₂ because the experimental proportion was lower than the theoretical proportion.

3.- Calculate the theoretical yield using the mass of F₂

76 g of F₂ --------------- 124 g of TiF₄

5 g of F₂ --------------- x

x = (5 x 124) / 76

x = 8.15 g of TiF₄

4 0

3 years ago

Consider the cell pt | h2 (1 atm); h+ (? m) || hg2cl2(s); cl− (1 m) | hg 2 h+ + 2 e − → h2 e 0 = 0.00 v hg2cl2 + 2 e − → 2 hg +

Dmitry [639]

Answer:

1.39

Explanation:

[Hg2Cl2]= 1M

[H^+] = ????

E°cell= 0.35V

E= 0.268 V

Therefore E for the reaction must -0.082 V

n= 2 moles of electrons

From Nernst Equation:

E= E°cell- 0.0592/n log [Red]/[Ox]

0.0268= 0.35- 0.0592/2 log 1/[Ox]^2

-0.082= -0.0296 log 1/[Ox]^2

log 1/[Ox]^2= 0.082/0.0296

log 1/[Ox]^2= 2.77

1/[Ox]^2=Antilog (2.77)

[Ox]^2=1.698×10^-3

[Ox] = 0.0412 M

But pH= -log [H^+]= -log(0.0412)= 1.385

3 0

3 years ago

Read 2 more answers

Abigail obtained 18.9 grams of calcium carbonate after performing a reaction. From her calculations, she knew she should have ob

zysi [14]

Answer:Percent error= 90.9%

Explanation:

Percent error or percentage error is defined as the percentage of the difference between a measured value usually from an experiment and an exact value in comparison to the exact number.

its formula is thus

Percent error = experimental value - exact or actual value /exact value x 100

=(18.9 - 9.9 /9.9 ) x 100= 9/9.9) x 100

0.909 x 100 = 90.90 = 90.9%

5 0

3 years ago

A gas mixture being used to simulate the atmosphere of another planet at 23°c consists of 337 mg of methane, 148 mg of argon, an

Karolina [17]

The total pressure of the mixture is 65.5 kPa.

According to Dalton's Law of Partial Pressure,

The partial pressure of gas = Mole fraction of gas × Total pressure

Total Pressure = Sum of all the gases partial pressures

The number of moles of methane is,

$Moles \: of \: methane \: (16 g/mol) = 337 \: mg \times \frac{1 g}{1000 mg} \times \frac{ 1 mol}{16 g }$

= 0.021 mols

The moles of methane are 0.021 mols.

The number of moles of the argon,

$Moles \: of \: argon (40 g/mol) = 148 \: mg \times \frac{ 1 g}{1000 mg } \times \frac{ 1 mol}{40 g}$

= 0.003 mols

The number of moles of argon is 0.003 mols.

The number of moles of nitrogen is,

$Moles \: of \: nitrogen (28 g/mol) = 296 \: mg \times \frac{ 1 g}{1000 mg} \times \frac{ 1 mol/}{28 g}$

= 0.010 mols

The number of moles of nitrogen is 0.010 mols.

The total number of moles is,

= 0.021 + 0.003 + 0.010

= 0.034 mols

$Mole \: fraction = \frac{ Moles \: of \: solute }{Total \: number \: of \: moles \: of \: soulte \: and \: solvent}$

$= \frac{ 0.010 }{ 0.034}$

= 0.29

$0.29 \: P _{total} = 19 \: kPa$

$P _{total} = \frac{ 19 \: kPa }{0.29}$

= 65.5 kPa

Therefore, the total pressure of the mixture is 65.5 kPa.

To know more about Dalton's law, refer to the below link:

brainly.com/question/14119417

#SPJ4

6 0

1 year ago

What are the chemical processes used to make chloroquine?

4vir4ik [10]

You spell Chlorine wrong but the process is called electrolysis

6 0

4 years ago