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Evgen [1.6K]
3 years ago
6

What would happen to the moon’s interia were to increase? A the moon will fly into space. B the moon will smash into Earth. C th

e moon will smash into pluto.
Chemistry
1 answer:
Montano1993 [528]3 years ago
5 0

Answer:

B

Explanation:

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A chemical reaction gives off 2100 kg of heat energy how many calories
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The chemical reaction that gives off 2100 Kg of heat energy has 501.9126 calories


calculation

convert KJ to  calories

that is

          1 KJ  =  0.239006 calories

        2100KJ= ?  calories

by close multiplication

= (2100 kj  x 0.239006)÷ 1 kj  =501.9126 calories

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3 years ago
In a decomposition reaction involving a gaseous product, what must be done for the reaction to reach equilibrium?
Vadim26 [7]

To prevent the gaseous product from escaping, the system must be sealed.

<h3>What are equilibrium and an example?</h3>

Equilibrium is characterized as a state of equilibrium or a stable situation in which conflicting forces balance one another out and no changes are taking place. In terms of economics, equilibrium occurs when supply and demand are equal. When you are composed and steady, you are in an equilibrium state.

<h3>What three types of equilibrium are there?</h3>

Equilibrium can be classified as either stable, unstable, or neutral.

<h3>Which four variables have an impact on equilibrium?</h3>
  • Equilibrium is influenced by the system's temperature, pressure, and concentration.
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Which of the liquids you tested (isopropyl alcohol, water, and glycerol) displayed the greatest surface tension (greatest interm
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1.) A balloon contains 0.126 mol of gas and has a volume of 2.74 L .
Ann [662]

Answer:

<u></u>

  • <u>Problem 1: 5.44L</u>
  • <u>Problem 2: 479mL</u>

Explanation:

<h2>Problem 1. </h2>

<u>a) Data:</u>

  • n₁ = 0.126 mol
  • V₁ = 2.74 L
  • n₂ = 0.126mol + 0.124mol
  • V₂ = ?
  • Conditions: constant temperature and pressure

<u>b) Physical principles:</u>

The volume occupied by a gas, when the temperature and pressure remain unchanged, is proportional to the number of moles of gas.

          \dfrac{n_1}{V_1}=\dfrac{n_2}{V_2}

<u>c) Solution:</u>

Solve for V₂ , substitute and compute:

        V_2=n_2\times\dfrac{V_1}{n_1}\\ \\\\  V_2=(0.126mol+0.124 mol)\times \dfrac{2.74L}{0.126mol}\\ \\ \\ V_2=5.44L

<h2>Problem 2.</h2>

<u>a) Data:</u>

  • n₁ = 0.547mol
  • V₁ = 295 mL
  • V₂ = ?
  • n₂ = 0.547mol + 0.342 mol
  • Conditions: constant temperature and pressure

<u>b) Physical principles:</u>

The same as above: the volume occupied by a gas, when the temperature and pressure remain unchanged, is proportional to the number of moles of gas.

          \dfrac{n_1}{V_1}=\dfrac{n_2}{V_2}

<u>c) Solution:</u>

Solve for V₂ , substitute and compute:

        V_2=n_2\times\dfrac{V_1}{n_1}\\ \\\\  V_2=(0.547mol+0.342 mol)\times \dfrac{295mL}{0.547mol}\\ \\ \\ V_2=479mL

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