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kenny6666 [7]
4 years ago
14

Doc is particularly interested in the last question posed by his supervisor, "Does the dye meet the ADI (Accepted Daily Intake)

values accepted in the United States?" .
Chemistry
1 answer:
Sophie [7]4 years ago
5 0

Yes, ADI (Accepted Daily Intake) values are accepted in the United States.

ADI is a result of toxicity studies or other toxicology information for direct food additive or color additive used in food. The ADI is based on the dose  level of the additive in animal studies that was shown to cause no adverse effect, multiplied an appropriate safety  factor (often 1/100). Prolonged ingestion of the additive at the ADI value is considered  cause no harm.

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Explain how research from the glomar challenger helped scientist support the theory of seafloor spreading?
Anna71 [15]

Drill cores from the ocean floor were dated and found to be very young compared to the age of the earth. This means the crust had to be formed recently, which can be explained by creation of crust at a spreading center.

3 0
4 years ago
Read 2 more answers
If 75 g of oxygen react how many grams of aluminum are required
daser333 [38]

Answer:

84.24 g

Explanation:

Given data:

Mass of oxygen = 75 g

Mass of Al required to react = ?

Solution:

Chemical equation:

4Al + 3O₂     →   2Al₂O₃

Number of moles of oxygen:

Number of moles = mass/ molar mass

Number of moles = 75 g/ 32 g/mol

Number of moles = 2.34 mol

Now we will compare the moles of oxygen with Al.

                         O₂         :          Al

                          3          :             4

                       2.34        :         4/3×2.34 = 3.12 mol

Mass of Al required:

Mass = number of moles × molar mass

Mass = 3.12 mol × 27 g/mol

Mass = 84.24 g

8 0
3 years ago
What is the hydronium concentration of a solution with a pH of 3.60
svetlana [45]
The answer is A 2.5x10-4M
4 0
3 years ago
10. When a 13.6 g sample of a compound containing only magnesium and oxygen is decomposed, 5.4 g of oxygen is obtained. What is
irinina [24]

Answer:5.4 g / 13.6 g *100

Explanation:Its is the correct answer

7 0
4 years ago
Read 2 more answers
What is the maximum mass of ammonia that can be formed when 36.52 grams of nitrogen gas reacts with 10.62 grams of hydrogen gas
k0ka [10]

The maximum mass of NH₃ that can be formed when 36.52 g of N₂ reacts with 10.62 g of H₂ is 44.35 g

<h3>Balanced equation </h3>

N₂ + 3H₂ —> 2NH₃

Molar mass of N₂ = 14 × 2 = 28 g/mol

Mass of N₂ from the balanced equation = 1 × 28 = 28 g

Molar mass of H₂ = 2 × 1 = 2 g/mol

Mass of H₂ from the balanced equation = 3 × 2 = 6 g

Molar mass of NH₃ = 14 + (3×1) = 17 g/mol

Mass of NH₃ from the balanced equation = 2 × 17 = 34 g

SUMMARY

From the balanced equation above,

28 g of N₂ reacted with 6 g of H₂ to produce 34 g of NH₃

<h3>How to determine the limiting reactant </h3>

From the balanced equation above,

28 g of N₂ reacted with 6 g of H₂

Therefore,

36.52 g of N₂ will react with = (36.52 × 6) / 28 = 7.83 g of H₂

From the above calculation, we can see that only 7.83 g out of 10.62 g of H₂ are required to react completely with 36.52 g of N₂.

Therefore, N₂ is the limiting reactant

<h3>How to determine the maximum mass of NH₃ produced </h3>

From the balanced equation above,

28 g of N₂ reacted to produce 34 g of NH₃

Therefore,

36.52 g of N₂ will react to produce = (36.52 × 34) / 28 = 44.35 g of NH₃

Thus, the maximum mass of NH₃ obtained from the reaction is 44.35 g

Learn more about stoichiometry:

brainly.com/question/14735801

#SPJ1

4 0
2 years ago
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