All categories

2 years ago

If 75 g of oxygen react how many grams of aluminum are required

Chemistry

1 answer:

daser333 [38]2 years ago

8 0

Answer:

84.24 g

Explanation:

Given data:

Mass of oxygen = 75 g

Mass of Al required to react = ?

Solution:

Chemical equation:

4Al + 3O₂ → 2Al₂O₃

Number of moles of oxygen:

Number of moles = mass/ molar mass

Number of moles = 75 g/ 32 g/mol

Number of moles = 2.34 mol

Now we will compare the moles of oxygen with Al.

O₂ : Al

3 : 4

2.34 : 4/3×2.34 = 3.12 mol

Mass of Al required:

Mass = number of moles × molar mass

Mass = 3.12 mol × 27 g/mol

Mass = 84.24 g

You might be interested in

(Question one) Pls help it’s 12:14 in the morning I just wanna go to bed :(

Goshia [24]

Answer:

climate

weather ?

Explanation:

7 0

3 years ago

Read 2 more answers

A sample of 211 g of iron (III) bromide is reacted with

Alisiya [41]

FeBr₃ ⇒ limiting reactant

mol NaBr = 1.428

<h3>Further explanation</h3>

Reaction

2FeBr₃ + 3Na₂S → Fe₂S₃ + 6NaBr

Limiting reactant⇒ smaller ratio (mol divide by coefficient reaction)

FeBr₃

211 g of Iron (III) bromide(MW=295,56 g/mol), so mol FeBr₃ :

$\tt n=\dfrac{mass}{MW}\\\\n=\dfrac{211}{295,56}\\\\n=0.714$

Na₂S

186 g of Sodium sulfide(MW=78,0452 g/mol), so mol Na₂S :

$\tt n=\dfrac{186}{78.0452}=2.38$

Coefficient ratio from the equation FeBr₃ : Na₂S = 2 : 3, so mol ratio :

$\tt FeBr_3\div Na_2S=\dfrac{0.714}{2}\div \dfrac{2.38}{3}=0.357\div 0.793$

So FeBr₃ as a limiting reactant(smaller ratio)

mol NaBr based on limiting reactant (FeBr₃) :

$\tt \dfrac{6}{3}\times 0.714=1.428$

6 0

3 years ago

Why is mercury the only metal to have been used in thermometers

MArishka [77]

I think because its the only one to be liquid at normal temperatures.

6 0

3 years ago

Which reaction is a decomposition reaction? A. 2KClO3 → 2KCl + 3O2 B. 4Na + O2 → 2Na2O C. ZnS + 3O2 → 2ZnO + 2SO2 D. 2NaBr + CaF

Vedmedyk [2.9K]

Answer:

Option A. 2KClO₃ → 2KCl + 3O₂

Explanation:

There are five basic general types of chemical reactions:

Decomposition reactions

Synthesis or combination reaction

Single replacement reactions

Double replacement reactions

Combustion reactions

The given reactions are:

2KClO₃ → 2KCl + 3O₂

Which is, indeed, a decomposition reaction because the reactant, KClO₃, is a single substance that undergoes a reaction in which it yields two new substances, known as products: KCl and O₂.

4Na + O₂ → 2Na₂O is a synthesis or combination reaction because two reactants, Na and O₂, combine for the formation of one single new product, Na₂O.

ZnS + 3 O₂ → 2ZnO + 2SO₂ is a single replacement reaction because oxygen is replacing Zn and S in ZnS to form ZnO and plus SO₂.

2NaBr + CaF₂ → 2NaF + CaBr₂ is a double replacement reaction because two ions (Br⁻ from NaBr and F⁻ from CaF₂) are exchanging places with other two ions (Na⁺ from NaBr and Ca²⁺ from CaF₂) two form two new ionic compounds (NaF and CaBr₂).

4 0

3 years ago

The 1995 Nobel Prize in Chemistry was shared by Paul Crutzen, F. Sherwood Rowland, and Mario Molina for their work concerning th

castortr0y [4]

Answer:

-162,5 kJ/mol

Explanation:

Cl(g) + 2O2(g) --> ClO(g) + O3(g) ΔH = 122.8 kJ/mol (as we used the reaction in the opposite direction, it will turn the enthalpy from exothermic to endothermic)

2O3(g) --> 3O2(g) ΔH = -285.3 kJ/mol

Cl(g) + O2(g) --> ClO(g) + O3(g) ΔH = 122.8 kJ

+ 2O3 (g) --> 3O2(g) ΔH = - 285.3 kJ

O3(g) + Cl(g) --> ClO(g) + 2O2(g) ΔH = 122.8 + (-285.3) = -162,5 kJ

4 0

3 years ago