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dalvyx [7]
3 years ago
7

Given the following unbalanced thermochemical equation, how much heat will be released from the combustion of 45.5 grams of CH4

in an excess of oxygen gas?
CH4(g) + 2O2(g) → CO2(g) + 2H2O(l) + 890 kJ
Chemistry
2 answers:
TEA [102]3 years ago
6 0

Answer:

2530kJ

Explanation:

a_sh-v [17]3 years ago
5 0
Heat  released   from  the  combustion  of   45.5  grams of  CH4 in  excess oxygen  gas is  calculated  as follows

calculate the number  of  CH4 moles used  = mass/molar mass
=  45.5  grams/ 15  g/mol  =2.84  moles

heat  released  is therefore= moles  x  890 kj

=   2.84  x 890=2527.6  kj/mol
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2 years ago
Which of the following solutions is acidic? [H3O+] = 1.0 x 10-10 M [H3O+] < 1.0 x 10-7 M [OH-] = 1.0 x 10-10 M [OH-] = 1.0 x
Burka [1]

Answer:

[OH-] = 1.0 x 10-10 M

Explanation:

The acidity of a solution can be determined directly from the concentration of the hydrogen ions and indirectly from the concentrations of the hydroxide ions.

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6 0
3 years ago
What is the mole, and why is it useful in chemistry?
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Explanation:

6 0
4 years ago
How much heat (in kj) is required to warm 13.0 g of ice, initially at -12.0 ∘c, to steam at 113.0 ∘c? the heat capacity of ice i
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5 0
4 years ago
Read 2 more answers
A solution is made by mixing 33.0 ml of ethanol, C2H6O and 67.0 ml of water. Assuming ideal behavior, what is the vapor pressure
ivann1987 [24]
Grams ethanol = 33 ml times .789 gms/ml = 26.037 gms 

<span>Moles ethanol = 26.037 gms / 46 gms/mole = .57 moles </span>

<span>Moles water = 67 ml or 67 grams/18 gms/mole = 3.22 moles </span>

<span>total moles = .57 + 3.72 = 4.29 moles </span>

<span>Mole fraction ethanol = .57 moles ethanol / 4.29 moles total = 0.13</span>

<span>Moles fraction water = 3.72 moles water / 4.29 moles total = 0.87</span>

<span>Partial pressure of ethanol = mole fraction ethanol (.13) _ times VP ethanol 43.9 torr) = 5.707 torr </span>

<span>partial pressure water = mole fraction water .87) times VP water (l7.5 torr) = 15.23 torr </span>

<span>Total vapor pressure over solution = 5.71 torr + 15.23 torr = 20.94 torr</span>
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3 years ago
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