Question

Given the following unbalanced thermochemical equation, how much heat will be released from the combustion of 45.5 grams of CH4 in an excess of oxygen gas?
CH4(g) + 2O2(g) → CO2(g) + 2H2O(l) + 890 kJ

Answer 1

Answer:

2530kJ

Explanation:

Answer 2

Heat  released   from  the  combustion  of   45.5  grams of  CH4 in  excess oxygen  gas is  calculated  as follows

calculate the number  of  CH4 moles used  = mass/molar mass
=  45.5  grams/ 15  g/mol  =2.84  moles

heat  released  is therefore= moles  x  890 kj

=   2.84  x 890=2527.6  kj/mol