Question

Use laws of exponents to simplify inside the parentheses of the given expression ((a ^ - 2 * b ^ 2)/(a ^ 2 * b ^ - 1)) ^ - 3

Answer 1

Answer:

$(\dfrac{a ^{ - 2 } b ^ 2}{a ^ 2 b ^ {- 1}}) ^ {- 3}=(a^{-2-2}b^{2+1})^-3=(a^{-4}b^{3})^{-3}=a^{12}b^{-9}$

Step-by-step explanation:

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