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gogolik [260]
3 years ago
6

Why does a passenger jumping out of a rapidly moving bus fall forqard with his face downwards​

Physics
1 answer:
Alex Ar [27]3 years ago
6 0

Answer:

Explanation:

It's Newton's first law of motion, and object in motion continues to stay in motion unless acted upon by an unbalanced force. In this case, your body is the force that's moving on the bus. When you jump(the unbalanced force) your body is still used to being in motion, which makes you fall and not land on your feet.  

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An airplane has wings, each with area A, designed so that air flows over the top of the wing at 265 m/s and underneath the wing
exis [7]

Answer

given,

Pressure on the top wing = 265 m/s

speed of underneath wings = 234 m/s

mass of the airplane =  7.2 × 10³ kg

density of air =  1.29 kg/m³

using Bernoulli's equation

 P_1 + \dfrac{1}{2}\rho v_1^2 = P_2 + \dfrac{1}{2}\rho v_2^2

 \Delta P =\dfrac{1}{2}\rho (v_2^2-v_1^2)

 \Delta P =\dfrac{1}{2}\times 1.29\times (265^2-234^2)

 \Delta P =9977.5 Pa

Applying newtons second law

2 Δ P x A - mg = 0

A =\dfrac{mg}{2\Delta P}

A =\dfrac{7.2\times 10^3 \times 9.8}{2\times 9977.5}

    A = 3.53 m²

7 0
3 years ago
Question 3. AP PHYSICS. Currently learning about torque so I assume you apply torque. I don't get it at all
8090 [49]

wow that is confusing


8 0
3 years ago
The cross section of a copper strip is 1.2 mmthick and 20 mm wide. There is a 25-A current through this cross section, with the
Naily [24]

To solve this problem it is necessary to use the concepts related to the Hall Effect and Drift velocity, that is, at the speed that an electron reaches due to a magnetic field.

The drift velocity is given by the equation:

V_d = \frac{I}{nAq}

Where

I = current

n = Number of free electrons

A = Cross-Section Area

q = charge of proton

Our values are given by,

I = 25 A

A= 1.2*20 *10^{-6} m^2

q= 1.6*10^{-19}C

N = 8.47*10^{19} mm^{-3}

V_d =\frac{25}{(1.2*20 *10^{-6})(1.6*10^{-19})(8.47*10^{19} )}

V_d = 7.68*10^{-5}m/s

The hall voltage is given by

V=\frac{IB}{ned}

Where

B= Magnetic field

n = number of free electrons

d = distance

e = charge of electron

Then using the formula and replacing,

V=\frac{(2.5)(25)}{(8.47*10^{28})(1.6*10^{-19})(1.2*10^{-3})}

V = 3.84*10^{-6}V

5 0
3 years ago
Which of the following are physical properties of nonmetals? a. they are brittle in the solid form b. most are gases at room tem
Black_prince [1.1K]

Option (D) is correct that all of the above are physical properties of non metals.

#$# THANK YOU #$#

6 0
3 years ago
Read 2 more answers
hergy A Sprinter runs at a a forward velocity of 10,9 m/s. If the sprinter has a mass of 72.5 kg, What is the Sprinter's Kinetic
Nina [5.8K]

Answer:

4306.8625 J or 344549/80J (fraction form)

Explanation:

kinetic energy= \frac{1}{2\\}mv²

= \frac{1}{2}×72.5×10.9²

= 4306.8625 J  or 344549/80 J

7 0
1 year ago
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