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3 years ago

If Maggie is walking at 1.4 m/s and accelerates at 0.20 m/s^2. What is her final velocity at the end of 100.0m

Physics

1 answer:

faltersainse [42]3 years ago

6 0

Answer:

6.478m/s

Explanation:

There are some assumptions to be made. To answer this problem, I assume that Maggie is walking in a straight line and that she initially starts off with a velocity of 1.4m/s.

Maggie initially walks at a speed of 1.4m/s. We are also told that the acceleration is 0.2m/s^2 and that she walked a total of 100m. Therefore our parameters are:

$v_i=1.4\frac{m}{s}\\a=0.2\frac{m}{s^2}\\d=100m\\v_f=?$

Looking up kinematic equations that contains these parameters are

$v_f^2=v_i^2+2ad\\v_f^2=(1.4\frac{m}{s})^2+2*(0.2\frac{m}{s^2})(100m)\\v_f^2=41.96\frac{m^2}{s^2}\\v_f=6.478\frac{m}{s}$

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Eva8 [605]

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6 0

3 years ago

You discover a binary star system in which one member is a15 solar mass main-sequence star and the other star is a 10 solar mass

Trava [24]

Answer:

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Explanation:

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3 years ago

Ram jumps onto a cement floor from a height of 1m and comes to rest in 0.1sec.

umka2103 [35]

Answer:

3/10 F.

Explanation:

Height ( h ) = 1m

Time taken ( t ) = 0.1 second

Height² ( h² ) = 9m

Time taken² ( t² ) = 1 second

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F = ma

= m ( v - u ) / t

= m √2gh / t

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F/F² = √h/h² × t/t²

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3 years ago

A (20*20) cm² loop has a resistance of 0.10 Ω. A magnetic field perpendicular to the loop is B = 4t - 2t², where B is in tesla a

Ilya [14]

Answer with Explanation:

We are given that

Area of loop= $(20\times 20) cm^2=400\times 10^{-4} m^2$

$1 cm^2=10^{-4} m^2$

Resistance, R= $0.1\Omega$

B= $4t-2t^2$

We know that magnetic flux

$\phi=BA$

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