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olchik [2.2K]
2 years ago
8

Are the equations correct? And how do you solve this completely?

Mathematics
2 answers:
mars1129 [50]2 years ago
7 0
Your equations are correct.
irina [24]2 years ago
5 0
Your equations are right. just use the substitution method to solve. substitute y because both have that on one side

it'll look like 40x+30=30x+60.
then just get x in one side. I showed my owrk in the photo

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What is the value of the expression shown? 4(-2) + (-10) + 3(-8)
Vlad [161]

Answer:

-42

Step-by-step explanation:

1. 4(-2)

2. 3(-8)

3. -8 + -10 + -24

4. cobine like terms

5. -42

7 0
2 years ago
Which of the values shown are potential roots of f(x) = 3x3 – 13x2 – 3x + 45? Select all that apply.
galina1969 [7]

Answer:

All potential roots are 3,3 and -\frac{5}{3}.

Step-by-step explanation:

Potential roots of the polynomial is all possible roots of f(x).

f(x)=3x^3-13x^2-3x+45

Using rational root theorem test. We will find all the possible or potential roots of the polynomial.

p=All the positive/negative factors of 45

q=All the positive/negative factors of 3

p=\pm 1,\pm 3,\pm 5\pm \pm 9,\pm 15\pm 45

q=\pm 1,\pm 3

All possible roots

\frac{p}{q}=\pm 1,\pm 3,\pm 5\pm \pm 9,\pm 15\pm 45,\pm \frac{1}{3},\pm \frac{5}{3}

Now we check each rational root and see which are possible roots for given function.

f(1)= 3\times 1^3-13\times 1^2-3\times 1+45\Rightarrow 32\neq 0

f(-1)= 3\times (-1)^3-13\times (-1)^2-3\times (-1)+45\Rightarrow \neq 32

f(-3)= 3\times (-3)^3-13\times (-3)^2-3\times (-3)+45\Rightarrow \neq -144

f(3)= 3\times (3)^3-13\times (3)^2-3\times (3)+45\Rightarrow =0\\\\ \therefore x=3\text{ Potential roots of function}

Similarly, we will check for all value of p/q and we get

f(-5/3)=0

Thus, All potential roots are 3,3 and -\frac{5}{3}.


5 0
2 years ago
Read 2 more answers
How do you do 4(x-3) you have to use distributive property to remove the parentheses..
Oksana_A [137]

Answer:

 4x -12

Step-by-step explanation:

Your question answers itself: you use the distributive property to remove the parentheses.

  4(x -3) = 4(x) +4(-3) = 4x -12

5 0
2 years ago
The altitude of the triangle ABC, segment DA, has been
slavikrds [6]

Answer: sin(B)= h/c

h= csin(b)

Area= 1/2acsin(B)

Step-by-step explanation: i got the answers frfr on edge smh yall know how that is

3 0
3 years ago
Read 2 more answers
I'll mark brainliest just tell me how to.
IRINA_888 [86]

Answer:

a = 12

b = 2

c = 11

Step-by-step explanation:

\frac{( {x}^{5}y  {z}^{4} )^{3} }{ {x}^{3} yz}  =  {x}^{a}  {y}^{b}  {z}^{c}  \\  \\ \frac{ {x}^{5 \times 3}y^{3}   {z}^{4 \times 3} }{ {x}^{3} yz}  =  {x}^{a}  {y}^{b}  {z}^{c}  \\  \\ \frac{ {x}^{15}y^{3}   {z}^{12} }{ {x}^{3} yz}  =  {x}^{a}  {y}^{b}  {z}^{c}  \\  \\  {x}^{15 - 3}  {y}^{3 - 1}  {z}^{12 - 1} =  {x}^{a}  {y}^{b}  {z}^{c} \\  \\  {x}^{12}  {y}^{2}  {z}^{11} =  {x}^{a}  {y}^{b}  {z}^{c}  \\  \\ equating \: like \: terms \: from \: both \: sides \\  \\  {x}^{12}  =  {x}^{a}  \:  \implies \: a = \boxed{ 12}\\  \\  {y}^{2}  =  {y}^{b}  \:  \implies \: b = \boxed{ 2} \\  \\  {z}^{11}  =  {z}^{c}  \:  \implies \: c = \boxed{ 11}

3 0
3 years ago
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