solution:
the kinetic energy acquired by the electron when it is accelerated y an electric field is
k=5.25\times10^-16j
the kinetic energy acquired by the electron will ne proportional to the potential difference between the plates across which the electric field is applied.it is given by,
e\Delta v = k
here,\delta v is the potential difference between the plates, e is the charge on an electron and k is the kinetic energy.
reassange the above expression
\delta v = \frac{k}{e}
the potential difference between the plates will be
\delta v = \frac{k}{e}
sunstitute 5.25 \times 10^-16j for k and 1.6 \times10^-19c for e is the above equation
\delta v =\frac{5.25\times10^-16j}{1.60\times10^-19c}
=3.28\times10^3v(\frac{1kv}{1000v})
=3.28kv
since the electrons will e accelerated towards the plate at higher potential.
hance p;ate b will be at higher potential
