Javelin at 72 meters/second. he throws it at an angle of 22 degrees. how fast is he throwing it in the x-direction in meters/sec
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The amount of extra electrons present on the negative surface is
57.2 x .
Distance =1.6 cm
Side = 24 cm
Electric field = 18000 N/C
Calculating the capacitance in the metal plates is necessary.
Using the capacitance formula
Putting the value
C = 8.85 x x (24 x
/1.6 x
C = 0.318 x F
V = Ed
V = 18000 x 1.6 x V
V = 288 V
<h3>Calculation of charge</h3>Q = CV
Q = 0.318 x x 288
Q = 91.54 x C
Charge on the both the plates
Q = +91.54 x
Q = - 91.54 x
Calculation of excess electrons on the negative surface:
n = q/e
n = 91.54 x / 1.6 x
n = 57.2 x electrons
Hence, the number of excess electrons on the negative surface is
57.2 x .
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Answer:
Explanation:
Given that,
The wavelength of light,
We need to find the frequency of the light. We know that,
So, the required frequency of light is equal to .