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Licemer1 [7]
3 years ago
13

Javelin at 72 meters/second. he throws it at an angle of 22 degrees. how fast is he throwing it in the x-direction in meters/sec

ond?
Physics
1 answer:
Elis [28]3 years ago
7 0
Assume this is 22 degrees from the horizontal (x).
A vector can always be split into components - in this case we can think of the world in two dimensions, meaning the 72ms-1 has a vertical and a horizontal component. We therefore know the hypotenuse of the triangle (the overall velocity) and the angle from the ground. Hence we can use trigonometry to solve this problem.

We know x and the hypotenuse, and we want to know the magnitude of the adjacent side (horizontal), therefore we can use cosx=adj/hyp

Substituting:

Cos(22) = adj/72
Adj = 72cos22 = 66.8ms-1 = 67ms-1 to 2sf
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Which has the most momentum?
boyakko [2]

Answer:

Both objects have the same magnitude of momentum.

Explanation:

If an object of mass m is moving at a velocity of v, the momentum of that object would be m\, v.

The 100\; {\rm g} (0.1\; {\rm kg}) object is moving at a speed of 1\; {\rm m\cdot s^{-1}}. The magnitude of the momentum of this object would be 0.1\; {\rm kg} \times 1\; {\rm m\cdot s^{-1}} = 0.1\; {\rm kg \cdot m \cdot s^{-1}}.

Similarly, the momentum of the 1\; {\rm g} (10^{-3}\; {\rm kg}) object moving at a speed of 100\; {\rm m\cdot s^{-1}} would be 10^{-3}\; {\rm kg} \times 100\; {\rm m\cdot s^{-1}} = 0.1\; {\rm kg \cdot m \cdot s^{-1}}.

Hence, the magnitude of momentum is the same for the two objects.

7 0
2 years ago
Physics double pivot question​
andriy [413]

Explanation:

Assuming the wall is frictionless, there are four forces acting on the ladder.

Weight pulling down at the center of the ladder (mg).

Reaction force pushing to the left at the wall (Rw).

Reaction force pushing up at the foot of the ladder (Rf).

Friction force pushing to the right at the foot of the ladder (Ff).

(a) Calculate the reaction force at the wall.

Take the sum of the moments about the foot of the ladder.

∑τ = Iα

Rw (3.0 sin 60°) − mg (1.5 cos 60°) = 0

Rw (3.0 sin 60°) = mg (1.5 cos 60°)

Rw = mg / (2 tan 60°)

Rw = (10 kg) (9.8 m/s²) / (2√3)

Rw = 28 N

(b) State the friction at the foot of the ladder.

Take the sum of the forces in the x direction.

∑F = ma

Ff − Rw = 0

Ff = Rw

Ff = 28 N

(c) State the reaction at the foot of the ladder.

Take the sum of the forces in the y direction.

∑F = ma

Rf − mg = 0

Rf = mg

Rf = 98 N

3 0
3 years ago
If 2.0×10^−4 C of charge passes a point in 2.0×10^−6 s , what is the rate of current flow?1.0×10^−10 A1.0×10^2 A4.0×10^−1 A4.0×1
Ipatiy [6.2K]

This problem is about the rate of the current. It's important to know that refers to the quotient between the electric charge and the time, that's the current rate.

I=\frac{Q}{t}

Where Q = 2.0×10^−4 C and t = 2.0×10^−6 s. Let's use these values to find I.

\begin{gathered} I=\frac{2.0\times10^{-4}C}{2.0\times10^{-6}\sec } \\ I=1.0\times10^{-4-(-6)}A \\ I=1.0\times10^{-4+6}A \\ I=1.0\times10^2A \end{gathered}

<em>As you can observe above, the division of the powers was solved by just subtracting their exponents.</em>

<em />

<h2>Therefore, the rate of the current flow is 1.0×10^2 A.</h2>
3 0
1 year ago
How can someone, like myself, share roughly 50% of their DNA with a 1st Cousin?
iragen [17]

Answer:

that's your 1st cousin which is your mom or dad's sibling's child sooo when you're that close and that related i would say that that would be the reason why.

Explanation:

hoped that helped!!

4 0
3 years ago
Can someone help me please? I’ve been trying to solve these questions all day.
qwelly [4]

#16

If we put a resistor in circuit it will slow the speed of current

Let's check ohms law

\\ \rm\Rrightarrow \dfrac{V}{I}=R

  • So if resistance is more current is less

#17

Again use ohms law

\\ \rm\Rrightarrow V=IR

\\ \rm\Rrightarrow V\propto I

  • Voltage must be increased
4 0
2 years ago
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