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4 years ago

8

A very small dinosaur, the Microraptor, was only 1.3 feet long, One of the larger dinosaurs, the diplodocus, was about 91 feet l

ong. How many times as long as the microraptor was the diplodocus?

2 answers:

snow_lady [41]4 years ago

6 0

Divide 90 by 1.3 and you will get your answer.

Do it yourself! just follow instructions!

<3

sukhopar [10]4 years ago

4 0

70 ft but i'm probably wrong

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X^2y^8/x^7y^6 if x= -2 and y= 4

damaskus [11]

Answer:

- $\frac{1}{2}$

Step-by-step explanation:

Given

$\frac{x^2y^8}{x^7y^6}$

= $\frac{y^{(8-6)} }{x^{(7-2)} }$

= $\frac{y^2}{x^5}$ , substitute values

= $\frac{4^2}{(-2)^{5} }$

= $\frac{16}{-32}$

= - $\frac{1}{2}$

7 0

3 years ago

Please help me to fill in the blanks

Alja [10]

Oooooo child i wish i could help

5 0

3 years ago

Hal and Renee play the following game a bag has 11 tiles in it each with a letter from the word probably in it Hal and Renee tak

Masteriza [31]

Answer:

<em>D. The game is not fair because the probability of Hal drawing a winning letter is less then the probability of Renee drawing a winning letter </em>

Explanation:

The word is not probably, which has 8 letters, but probability, which has 11 letters

<u>1. Hal</u>

Probability of drawing a vowel

The vowels are: o, a, i, i, and y: 5

The total number of letters in the bag is 11.

Probability of vowel = 5 / 11

<u>2. Renee</u>

Probability of drawing a consonant

The consonants are: p, r, b, b, l, t, and y: 7

Probability of a drawing a consonant: 7 /11

<h2>Conclusion</h2>

As you see, the probability of drawing a vowel (5/11), which is the winning letter for Hal, is less than the probability of drawing a consonant (7/11), which is the winning letter of Renee. Then,

The game is not fair because the probability of Hal drawing a winning letter is less then the probability of Renee drawing a winning letter.

8 0

4 years ago

2 u + 12 < 23<br> 0,1 d + 8 > 0<br> 3 - 4 r > 7<br> 13 < 2 z + 3<br> 6 ≥ 9 - 0, 15 i

BartSMP [9]

Answer:

Part 1) $u< 5.5$

Part 2) $d > -80$

Part 3) $r < -1$

Part 4) $z>5$

Part 5) $i\geq 20$

Step-by-step explanation:

<u><em>The question is</em></u>

Solve each inequality for the indicated variable

Part 1) we have

$2u+12$

subtract 12 both sides

$2u< 23-12\\2u$

Divide by 2 both sides

$u< 5.5$

The solution is the interval (-∞,5.5)

In a number line the solution is the shaded area at left of u=5.5 (open circle)

The number 5.5 is not included in the solution

Part 2) we have

$0.1d+8 >0$

subtract 8 both sides

$0.1d > -8$

Divide by 0.1 both sides

$d > -80$

The solution is the interval (-80,∞)

In a number line the solution is the shaded area at right of d=-80 (open circle)

The number -80 is not included in the solution

Part 3) we have

$3-4r> 7$

Subtract 3 both sides

$-4r>7-3\\-4r>4$

Divide by -4 both sides

Remember that, when you multiply or divide both sides of an inequality by a negative number, you must reverse the inequality symbol

$r < -1$

The solution is the interval (-∞,-1)

In a number line the solution is the shaded area at left of r=-1.1 (open circle)

The number -1.1 is not included in the solution

Part 4) we have

$13< 2z+3$

Subtract 3 both sides

$13-3$

Divide by 2 both sides

$5$

Rewrite

$z>5$

The solution is the interval (5,∞)

In a number line the solution is the shaded area at right of z=5 (open circle)

The number 5 is not included in the solution

Part 5) we have

$6\geq 9-0.15i$

Subtract 9 both sides

$6-9\geq -0.15i\\-3\geq -0.15i$

Divide by -0.15 both sides

Remember that, when you multiply or divide both sides of an inequality by a negative number, you must reverse the inequality symbol

$20\leq i$

Rewrite

$i\geq 20$

The solution is the interval [20,∞)

In a number line the solution is the shaded area at right of i=20 (closed circle)

The number 20 is included in the solution

6 0

4 years ago

What is the answer to 93+(68+7)

Rasek [7]

93+(68+7)do whats in the parenthesis first

93(75)

multiply them together

6975 is your answer plz rate my answer as brainliest

7 0

3 years ago