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3 years ago

Which statement best describes frequency and pitch?

Physics

2 answers:

Crazy boy [7]3 years ago

8 0

A. frequency and pitch are the same as wavelength and velocity.

Sorry if im wrong

balandron [24]3 years ago

6 0

<h2>Answer:</h2>

<u>The right choice is </u><u>D. Pitch is how frequency is perceived</u>

<h2>Explanation:</h2>

Pitch perception allows us to order sounds on a musical scale. In simpler words pitch is the quality that makes it possible to judge sounds as "higher" and "lower" in the sense associated with musical melodies. So it is related to frequencies in the term that a sound having higher frequencies will have higher pitch and vice versa. SO we distinguish the sounds pitch by their frequencies.

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Select the statement that correctly lists the forces from strongest to weakest. (2 points)

Vilka [71]

Strong Nuclear force: it is the short range force and strongest fundamental force in all type of forces.

Electromagnetism: this is the force due to magnetic and electric behavior of the particles. It is moderate type of force and its range is more than Nuclear force.

Weak Nuclear Force: This force is also short range force which act between the nucleoside. But this force is also moderate type of force

Gravitational force: this force is between two point masses and least order of force. also the range of this force is upto infinite.

so the correct order of this fundamental force is

<em>strong nuclear, electromagnetism, weak nuclear, gravitational</em>

5 0

3 years ago

A body is projected from the ground at an angle of 30° with the horizontal at an initial speed of 128 ft/s. Ignoring air frictio

Elanso [62]

Answer

given,

v = 128 ft/s

angle made with horizontal = 30°

now,

horizontal component of velocity

vx = v cos θ = 128 x cos 30° = 110.85 ft/s

vertical component of velocity

vy = v sin θ = 128 x sin 30° = 64 m/s

time taken to strike the ground

using equation of motion

v = u + at

0 =-64 -32 x t

t = 2 s

total time of flight is equal to

T = 2 t = 2 x 2 = 4 s

b) maximum height

using equation of motion

v² = u² + 2 a h

0 = 64² - 2 x 32 x h

64 h = 64²

h = 64 ft

c) range

R = v_x × time of flight

R = 110.85 × 4

R = 443.4 ft

4 0

3 years ago

An ideal air-filled parallel-plate capacitor has round plates and carries a fixed amount of equal but opposite charge on its pla

dusya [7]

Answer:

C). $U_f = \frac{U_0}{2}$

Explanation:

As we know that capacitance of a given capacitor is

$C = \frac{\epsilon_0 A}{d}$

now we know that energy stored in the capacitor plates

$U_0 = \frac{Q^2}{2C}$

here if all the dimensions of the capacitor plate is doubled

then in that case

$C' = \frac{\epsilon_0 (4A)}{2d}$

here area becomes 4 times on doubling the radius and the distance between the plates also doubles

So new capacitance is now

$C' = 2C$

so capacitance is doubled

now the final energy stored between the plates of capacitor is given as

$U_f = \frac{Q^2}{2C'}$

so the final energy is

$U_f = \frac{Q^2}{4C}$

$U_f = \frac{U_0}{2}$

4 0

3 years ago

A 1.5 kg ball is dropped from a height of 2.Gm. Assuming energy is

Vikki [24]

Answer:

Plug in the given values and solve for the final velocity. Remember, when the ball is on the ground it has a height of zero.

Explanation:

6 0

2 years ago

An object at rest on a flat, horizontal surface explodes into two fragments, one seven times as massive as the other. The heavie

leva [86]

To solve the problem it is necessary to apply conservation of the moment and conservation of energy.

By conservation of the moment we know that

$MV=mv$

Where

M=Heavier mass

V = Velocity of heavier mass

m = lighter mass

v = velocity of lighter mass

That equation in function of the velocity of heavier mass is

$V = \frac{mv}{M}$

Also we have that $m/M = 1/7 times$

On the other hand we have from law of conservation of energy that

$W_f = KE$

Where,

W_f = Work made by friction

KE = Kinetic Force

Applying this equation in heavier object.

$F_f*S = \frac{1}{2}MV^2$

$\mu M*g*S = \frac{1}{2}MV^2$

$\mu g*S = \frac{1}{2}( \frac{mv}{M})^2$

$\mu = \frac{1}{2} (\frac{1}{7}v)^2$

$\mu = \frac{1}{98}v^2$

$\mu = \frac{1}{g(98)(5.1)}v^2$

Here we can apply the law of conservation of energy for light mass, then

$\mu mgs = \frac{1}{2} mv^2$

Replacing the value of $\mu$

$\frac{1}{g(98)(5.1)}v^2 mgs = \frac{1}{2}mv^2$

Deleting constants,

$s= \frac{(98*5.1)}{2}$

$s = 249.9m$

7 0

4 years ago