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3 years ago

Which statement best describes frequency and pitch?

Physics

2 answers:

Crazy boy [7]3 years ago

8 0

A. frequency and pitch are the same as wavelength and velocity.

Sorry if im wrong

balandron [24]3 years ago

6 0

<h2>Answer:</h2>

<u>The right choice is </u><u>D. Pitch is how frequency is perceived</u>

<h2>Explanation:</h2>

Pitch perception allows us to order sounds on a musical scale. In simpler words pitch is the quality that makes it possible to judge sounds as "higher" and "lower" in the sense associated with musical melodies. So it is related to frequencies in the term that a sound having higher frequencies will have higher pitch and vice versa. SO we distinguish the sounds pitch by their frequencies.

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Lelu [443]

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2 years ago

A skydiver falls toward the ground at a constant velocity. Which statement best applies Newton’s laws of motion to explain the s

Tema [17]

Answer:

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7 0

3 years ago

Read 2 more answers

Find the horizontal component and the vertical component

aleksandr82 [10.1K]

Answer:

v=3.66,h-3.66

Explanation:

vertical = 10sin60 - 10sin 30

horizontal =10cos60 + 10cos 30

v = 10×0.8660-10×0.5

h = 10×0.5 + 10 × 0.8660

v=8.660-5.0 = 3.66

h= 5.0-8.660 = -3.66

8 0

3 years ago

Water evaporating from a pond does so as if it were diffusing across an air film 0.15 cm thick. The diffusion coefficient of wat

QveST [7]

Answer:

The water level will drop by about 1.24 cm in 1 day.

Explanation:

Here Mass flux of water vapour is given as

$j_{H_2O}=\frac{D}{l} \bigtriangleup c$

where

$j_{H_2O}$ is the mass flux of the water which is to be calculated.

D is diffusion coefficient which is given as $0.25 cm^2/s$

l is the thickness of the film which is 0.15 cm thick.
$\bigtriangleup c$ is given as

$\bigtriangleup c= \frac{P_{sat}-P_a}{RT}$

In this

$P_{sat}$ is the saturated water pressure, which is look up from the saturated water property at 20°C and 0.5 saturation given as 2.34 Pa

$P_a$ is the air pressure which is given as 0.5 times of $P_{sat}$

R is the universal gas constant as $8.314 kJ/kmol-K$

T is the temperature in Kelvin scale which is $20+273= 293K$

By substituting values in the equation

$\bigtriangleup c= \frac{P_{sat}-P_a}{RT} \\ \bigtriangleup c= \frac{P_{sat}-0.5P_{sat}}{RT} \\ \bigtriangleup c= \frac{0.5P_{sat}}{RT} \\ \bigtriangleup c= \frac{0.5 \times 2.34}{8.314 \times 293} \\\bigtriangleup c= 0.48 mol/m^3$