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pogonyaev
4 years ago
12

Although not explicitly discussed in the chapter, packet size would seem to have an impact on transmission time. Discuss whether

or not this is true and explain why. Specifically compare the concept of the number of bits that constitute the data portion of the packet and the number of bits that constitute the address portion of the packet. Remember that the address is overhead and it has an impact on data transmission rates.Offer a comprehensive example comparing packet sizes and resulting transmission times. For example, look at some of your e-mail messages and compare the number of bytes that constitute the message with the number of bytes for the address. Compute the results for several e-mails and give your conclusions.
Engineering
1 answer:
netineya [11]4 years ago
7 0

Answer and Explanation:

It is True that packet size increases the transmission time of the packets. This is because packet transmission would be impacted depending on the packet size, whether it is large or small. Here comes the concept of bandwidth of the medium. For a particular bandwidth of the medium, if the packet is small then many such packets can pass through the medium at a given time, rather than less packets at a given time when the packet sizes are larger. Transmission time of a packet = Packet size / Bandwidth of the medium.

If the bandwidth is high, the transmission time will be less. Also, if the packet size increases then, as we saw above the transmission time will increase.

Every packet has to have a header information in which there will be several information and data about the packet and the protocol it follows, also what is the source and destination of the packet. The information contained in the header of a packet may vary in case of different protocols. The address portion of the packet is a overhead but us actually necessary when the packet needs to be transferred from a source to a destination using a protocol. The size of the header varies from protocol to protocol and is an overhead and has impact on data transmission rates since size of the packet increases because of the header.

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It is desired to produce and aligned carbon fiber-epoxy matrix composite having a longitudinal tensile strength of 610 MPa. Calc
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Answer:

volume fraction of fibers is 0.4

Explanation:

Given that for the aligned carbon fiber-epoxy matrix composite:

Diameter (D) = 0.029 mm

Length (L) = 2.3 mm

Tensile strength (\sigma_{cd}) = 610 MPa

fracture strength (\sigma_f) = 5300 MPa

matrix stress (\sigma_m) =  17.3 MPa

fiber-matrix bond strength (\tau_c) = 19 MPa

The critical length is given as:

L_C=\sigma_f(\frac{D}{2\tau_c} )=5300*10^6(\frac{0.029*10^{-3}}{19*10^6} )=8.1*10^{-3}=8.1mm

Since the critical length is greater than the length, the aligned carbon fiber-epoxy matrix composite can be produced.

The longitudinal strength is given by:

\sigma_{cd}=\frac{L*\tau_c}{D} .V_f+\sigma_m(1-V_f)

making Vf the subject of the formula:

V_f=\frac{\sigma_{cd}-\sigma_m}{\frac{L*\tau_c}{D} -\sigma_m}

Vf is the volume fraction of fibers.

Therefore:

V_f=\frac{\sigma_{cd}-\sigma_m}{\frac{L*\tau_c}{D} -\sigma_m}=\frac{610*10^6-17.3*10^6}{\frac{2.3*10^{-3}*19*10^6}{0.029*10^{-3}}-17.3*10^6} } =0.4

volume fraction of fibers is 0.4

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B. to achieve sustainable development
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Answer:

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The temperature of the fin at x = 10 cm = 0.10 m from the base can be calculated from the temperature variation with distance formula for a very long fin.

(T - T∞) = (T₀ - T∞)e⁻ᵐˣ

T = T(x) = temperature at any point along the fin

T∞ = temperature at the tip of the fin = ambient temperature = 25°C

T₀ = temperature at the base of thw fin = 50°C

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A = surface area in contact with the base = πD²/4 = π(0.03)²/4 = 0.0007071 m²

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