Gas turbines extract the energy from combustion gas
and heat engines convert thermal and chemical energy to mechanical energy
gas is considered a chemical so i'm pretty sure it is considered one
Elevators makes it go up and down
Answer:
Force per unit plate area is 0.1344 
Solution:
As per the question:
The spacing between each wall and the plate, d = 10 mm = 0.01 m
Absolute viscosity of the liquid, 
Speed, v = 35 mm/s = 0.035 m/s
Now,
Suppose the drag force that exist between each wall and plate is F and F' respectively:
Net Drag Force = F' + F''
where
= shear stress
A = Cross - sectional Area
Therefore,
Net Drag Force, F = 
Also
F = 
where
= dynamic coefficient of viscosity
Pressure, P = 
Therefore,
Answer:
W=-109.12 kJ/kg
Q=-76.34 kJ/kg
Explanation:
The needed work W we will calculate by using the work equation for polytropic process and the heat transfer Q we will calculate by using the energy balance equation.
Before the calculations we first need to determine the final temperature T2. We will do that by using the given initial temperature T1 = 10°C, the given initial p_1 = 120 kPa and final p_2 = 800 kPa pressure and the polytropic index n = 1.2. Before the calculation we need to express the temperature in K units.
T1 = 10°C + 273 K = 283 K
T2 = ((p_2/p_1)^(n-1)/n)* T1
T2 = 388 K
Now we can use the heat capacity C_v, = 0.3122 kJ /kg K and the temperatures T1 and T2 to determine the change in internal energy ΔU.
ΔU = C_v*(T2-T1)
ΔU = 32.78 kJ/kg
to determine the work we will also need the initial v1 and final v2 specific volume. The initial specific volume v1 we can determine from the ideal gas equation. For the calculation we will need the initial pressure p_1, temperature T1 and the specific gas constant R = 0.2081 kJ /kg K.
v1=R*T1/p_1
v1=0.4908 m^3/kg
For the final specific volume we need to replace the initial temperature and pressure with the final.
v2=R*T2/p_2
v2=0.1009 m^3/kg
The work W is then:
W=p_2*v2-p_1*v1/n-1
W=-109.12 kJ/kg
The heat transfer Q we can calculate form the energy balance equation. For the calculation we will need the calculated work W and the change in internal energy ΔU.
Q=W+ΔU
Q=-76.34 kJ/kg
