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koban [17]
2 years ago
12

In an experiment, one of the forces exerted on a proton is F⃗ =−αx2i^, where α=12N/m2. What is the potential-energy function for

F⃗ ? Let U=0 when x=0.
Physics
1 answer:
Blizzard [7]2 years ago
7 0

Answer:

The potential energy is -4x^3

Explanation:

Given that,

Force F=-\alpha x^2 i

We need to calculate the potential energy

Using formula of work done

\Delta U=F(x) dx

Put the value of F

\Delta U=-\alpha x^2\ dx

On integration

U=-\alpha \dfrac{x^3}{3}+C

U=-\dfrac{\alpha x^3}{3}+C...(I)

U = 0, x = 0 so C = 0

Put the value of c and α in equation (I)

U=-\dfrac{12x^3}{3}+0

U=-4x^3

Hence, The potential energy is -4x^3

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