<span>The waves with the lowest energy and lowest frequencies of the electromagnetic spectrum are the "Radio waves"
So, option B is your answer
Hope this helps!
</span>
<u>Answer:</u>
The acceleration of the car is 
<u>Explanation:</u>
In the question it is given that car initially heads north with a velocity
. It then accelerates for
and in the end its velocity is
.
initial velocity 
time 
final velocity 
The equation of acceleration is


The value of acceleration is positive, here since the car is speeding up. If it was slowing down the value of acceleration would be negative.
Answer:

Explanation:
As we know that the angular acceleration of the wheel due to friction is constant
so we can use kinematics

so we have



now time required to completely stop the wheel is given as



now time required to stop the wheel is given as


Answer:
a fad diet is basically a diet that was a trend or that was popular for a short amount of time and makes unreasonable claims for fast and very much wanted results
Explanation: