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frez [133]
3 years ago
12

If there are 50 grams of U-238 on day zero of radioactive decay, how much will there be after 4.5 billion years

Physics
2 answers:
snow_lady [41]3 years ago
4 0
We use the formula of the half-life to calculate for the remaining U-238 after 4.5 billion years. The formula is expressed as A = A₀ (1/2)^(t/h) where A is the final amount, A₀ is the initial amount of the substance, t is the time and h is the half-life of the substance wherein for U-238 h is equal to 4.47 billion years.

<span>A = A₀ (1/2)^(t/h)
</span>A = 50 (1/2)^(4.5 / 4.47)
A = 24.88 g
kobusy [5.1K]3 years ago
4 0

25 if using usatsyprep

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A roller coaster begins at the top of a hillIf it accelerates at the rate of 2m/s ^2 And has a mass of 2000kg, what net force is
Luden [163]

The correct answer to the question is : 4000 N

EXPLANATION:

As per the question, the mass of the roller coaster is given as m = 2000 kg

The acceleration of the roller coaster is given as a = 2m/s2

We are asked to calculate the net force acting on the roller coaster.

From Newton's second laws of motion,we know that net external force acting on a particle is equal to the product of mass with acceleration of the particle.

Mathematically it is written as-

F = ma

Hence,net force acting on the roller coaster is calculated as-

F = 2000Kg×2m/s2

= 4000 N.

Here, Newton (N) is the unit of force.

Hence,net force acting on the roller coaster is 4000 N.

5 0
3 years ago
PLEASE HELP ASAP
morpeh [17]
A is the correct answer
7 0
3 years ago
A tennis player smashes a ball of mass m horizontally at a vertical wall. The ball rebounds at the same speed v with which it st
Morgarella [4.7K]

Answer:

<em> B.0</em>

Explanation:

Change in momentum: This is defined as the product of mass and change in velocity of a body. or it can be defined as the product of force and time of a body. The fundamental unit of change in momentum is kg.m/s

Change in momentum = M(V-U)......................... Equation 1

where M = mass of the ball, V = final velocity of the ball, U = initial velocity of the ball.

Let: M = m kg and V = U = v m/s

Substituting these values into equation 1

Change in momentum = m(v-v)

Change in momentum = m(0)

Change in momentum = 0 kg.m/s

<em>Therefore the momentum of the ball has not changed.</em>

<em>The right option is B.0</em>

5 0
3 years ago
Is work required to pull a nucleon out of an atomic nucleus? Does the nucleon, once outside the nucleus, hove more mass than it
olga2289 [7]
<span>Work is required to pull a nucleon out of an atomic nucleus. It has more mass outside the nucleus.</span>
6 0
3 years ago
assume the suns total energy output is 4.0 * 10^26 watts, and 1 watt is 1 joule/second. assume 4.3 * 10^-12 J is released from e
Dmitry [639]

Answer:

9.3\cdot 10^{37}

Explanation:

Power is defined as the energy produced (E) per unit of time (t):

P= \frac{E}{t}

This means that the energy produced in the Sun each second (1 s), given the power P=4.0\cdot 10^{26}W, is

E=Pt=(4.0\cdot 10^{26}W)(1s )=4.0\cdot 10^{26} J

Each p-p chain reaction produces an amount of energy of

E_1 = 4.3\cdot 10^{-12} J

in order to get the total number of p-p chain reactions per second, we need to divide the total energy produced per second by the energy produced by each reaction:

n=\frac{E}{E_1}=\frac{4.0\cdot 10^{26} J}{4.3\cdot 10^{-12} J}=9.3\cdot 10^{37}

3 0
3 years ago
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