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3 years ago

12

PLS ANSWER ASAP I WILL MAKE YOU BRAINLIEST ( Number 10.)

2 answers:

OLEGan [10]3 years ago

6 0

Answer:

x=160°

since the sum of angles of the shape measures 540°

by summing up the values, we have

3x=480 divide both sides by 3

x=160°

Alecsey [184]3 years ago

4 0

Answer:

<h2>160°</h2><h2>I hope i am not too late </h2><h2 />

Step-by-step explanation:

$Sum\:of\:angles\: = 540\\\\\frac{1}{2}x +\frac{1}{2} x +(x-15)+(x-25)+100=540\\\\=\frac{1}{2}x+\frac{1}{2}x+x-15+x-25+100=540\\\\Group\: like \:terms\\\frac{1}{2}x+\frac{1}{2}x+x+x-15-25+100=540\\\\Add\:similar\:elements \::\frac{1}{2}x+\frac{1}{2}x=2\times\frac{1}{2}x\\2\times\frac{1}{2}x+x+x-15-25+100=540\\\\Simplify\\x+2x-15-25+100=540\\Simplify\\3x +60 = 540\\\\3x = 540-60\\3x = 480\\Divide \:both\:sides\:of\:the\:equation \:by\:3\\\\\frac{3x}{3} = \frac{480}{3}\\ x =160$

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Relation sheep between the value of 6s in 6600

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The first 6 is equal to 6,000. The second 6 is equal to 600. 6,000 is 10 times greater than 600.

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4 years ago

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astraxan [27]

Answer:

a)0.6192

b)0.7422

c)0.8904

d)at least 151 sample is needed for 95% probability that sample mean falls within 8$ of the population mean.

Step-by-step explanation:

Let z(p) be the z-statistic of the probability that the mean price for a sample is within the margin of error. Then

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a.

z(p)= $\frac{8*\sqrt{30}}{50 }$ ≈ 0.8764

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b.

z(p)= $\frac{8*\sqrt{50}}{50 }$ ≈ 1.1314

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c.

z(p)= $\frac{8*\sqrt{100}}{50 }$ ≈ 1.6

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d.

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3 years ago

If a4 = 625, what does (a) equal?

Reika [66]

I'm assuming you meant to write a^4 = 625.

If that is the case, then note how 625 = 25^2, and how a^4 is the same as (a^2)^2

So we go from this

a^4 = 625

to this

(a^2)^2 = 25^2

Apply the square root to both sides and you'll end up with: a^2 = 25

From here, apply the square root again to end up with the final answer: a = 5 or a = -5

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a^4 = (-5)^4 = (-5)*(-5)*(-5)*(-5) = 25*25 = 625

a^4 = (5)^4 = (5)*(5)*(5)*(5) = 25*25 = 625

Both values of 'a' work out

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3 years ago

What is 12 in simplified radical form

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Hello!

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