Answer:
mass CaI2 = 23.424 Kg
Explanation:
From the periodic table we obtain for CaI2:
⇒ molecular mass CaI2: 40.078 + ((2)(126.90)) = 293.878 g/mol
∴ mol CaI2 = (4.80 E25 units )×(mol/6.022 E23 units) = 79.708 mol CaI2
⇒ mass CaI2 = (79.708 mol CaI2)×(293.878 g/mol) = 23424.43 g
⇒ mass CaI2 = 23.424 Kg
Answer:
9.34 cm³
Explanation:
From the question given, we obtained the following data:
Mass of magnesium = 16.24 g
Volume of magnesium =.?
To obtain the volume of the magnesium sample, we simply apply the formula for calculating the density of samples. This is illustrated below:
Mass of magnesium = 16.24 g
Density of magnesium 1.738 g/cm³
Volume of magnesium =.?
Density = mass /volume
1.738 = 16.24/volume
Cross multiply
1.738 × volume = 16.24
Divide both side by 1.738
Volume of magnesium = 16.24/1.738
Volume of magnesium = 9.34 cm³
Therefore, the density of the magnesium sample is 9.34 cm³.
Election current because voltage is a measurement, information doesn't apply to all electrical devices and the wires within are usually copper bc it conducts and hardly ever will the wires be anything different because copper is cheap
Answer:
d = 3.11 g /cm³
Explanation:
Volume -
The volume of a cuboidal object can be calculated by multiplying the length , width and height ,
Hence , Volume ( V ) = l * w * h ,
From the question ,
l = 8.2 cm
w = 3.8 cm
h = 7 cm
Hence, the volume is ,
V = l * w * h
V = 8.2 cm * 3.8 cm * 7 cm
V = 218.12 cm³
Density -
Density of a substance is given as the mass divided by the volume ,
Hence,
d = m / V
From the question,
m = 0.68 kg
since ,
1 kg = 1000g
m = 0.68 * 1000 = 680 g
V = 218.12 cm³ ( calculated above )
Hence , the value of density can be calculated by using the above equation,
d = m / V
d = 680 g / 218.12 cm³
d = 3.11 g /cm³
