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AfilCa [17]
3 years ago
14

What is the volume of a 16.24 g sample of magnesium in cubic centimeters? Show a numerical setup and result for credit.

Chemistry
1 answer:
Virty [35]3 years ago
6 0

Answer:

9.34 cm³

Explanation:

From the question given, we obtained the following data:

Mass of magnesium = 16.24 g

Volume of magnesium =.?

To obtain the volume of the magnesium sample, we simply apply the formula for calculating the density of samples. This is illustrated below:

Mass of magnesium = 16.24 g

Density of magnesium 1.738 g/cm³

Volume of magnesium =.?

Density = mass /volume

1.738 = 16.24/volume

Cross multiply

1.738 × volume = 16.24

Divide both side by 1.738

Volume of magnesium = 16.24/1.738

Volume of magnesium = 9.34 cm³

Therefore, the density of the magnesium sample is 9.34 cm³.

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Answer:

  • <u>Cadmium has larger atomic radius than sulfur.</u>

Explanation:

Down a period, atomic radii decrease from left to right due to the increase in the number of protons and electrons across a period: when a proton is added the pull of the electrons towards the nucleus is larger, so the size of the atom decreases.

Hence, you can compare the elements that belong to a same period and predict that the atom with lower atomic number (number of protons) will haver larger atomic radius. With that:

  • Oxygen and fluorine are in the period 3, being oxygen to the left of fluorine, so oxygen is larger than fluorine.

  • Sulfur and chlorine are in the period 4, being sulfur to the left of chlorine, so sulfur is larger than chlorine.

Now see whan happens down a group. Atomic radius increases from top to bottom within a group due to electron shielding. That permits you to compare the size of the elements in a group:

  • Fluorine and chlorine are in the same group (17), with chlorine directly below fluorine, so the atomic radius of chlorine is larger than the atomic radius of fluorine.

  • Sulfur and oxygen are in the same group (16), with sulfur directlly below oxygen, so sulfur the atomic radius of sulfur is larger than the atocmi radius of oxygen.

So far, you can rank the atomic radius of sulfur, chlorine, fluorine, and oxygen, in increasing order as:

  • O < F < Cl < S, concluding that O, F, and Cl have smaller atomic radius than S.

Cadmiun, Cd, is to the left and below sulfur, so both electron shielding (down a group) and increase of the number of protons (down a period) lead to predict the cadmium has a larger atomic radius than sulfur.

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Explanation:

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***BRAINLIEST ASNWERRR***<br>How many grams are in 34.2 moles of Lithium (Li)?​
Step2247 [10]

Mass of Li = 237.38 g

<h3>Further explanation</h3>

The mole itself is the number of particles contained in a substance amounting to 6.02.10²³  

\large {\boxed {\boxed {\bold {mol = \frac {mass} {molar \: mass}}}}

<h3>Known</h3>

Moles of Li = 34.2

Molar mass(MW) of Li = 6.941 g/mol

then mass of Lithium (Li) :

\tt mol=\dfrac{mass}{MW}\\\\mass=mol\times MW\\\\mass=34.2\times 6,941~g/mol\\\\mass=\boxed{\bold{237.38~g}}

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