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Setler [38]
3 years ago
12

Fireworks that contain metallic salts such as sodium, strontium, and barium can generate bright colors. A technician investigate

s what colors are produced by the metallic salts by performing flame tests. During a flame test, a metallic salt is heated in the flame of a gas burner. Each metallic salt emits a characteristic colored light in the flame. 3. State how bright-line spectra viewed through a spectroscope can be used to identify the metal ions in the salts used in the flame tests. 4. Explain, in terms of electrons, how a strontium salt emits colored light. 5. Explain why the electron configuration of 2-7-1-1 represents a sodium atom in an excited state.
Chemistry
1 answer:
Alex777 [14]3 years ago
8 0

Answer:

See explanation below

Explanation:

3. Each atom has unique electron energy level when compared to other, when electron relaxes from an excited energy level, it emits energy in the form of electromagnetic waves with energy equals to the difference between energy of ground and excited state. As electromagnetic wave wavelength obeys planck relation

c = \lambda f

And the energy of each photon in electromangetic wave of specific frequency is

E=hf

Where h is planck's constant

We can see that the wavelength, which determines color and position of bright line in spectroscope corresponds directly to the energy of electromagnetic wave, and thus, the characteristic energy of atom.

4. From the answer above, you now know that electronic transition can emit electron with specific wavelength. In strontium, emission of colored light occurs by the relaxation of electrons in excited state such that the difference between excited energy level and ground level falls in the energy of visible light spectral range.

5. In Na, ground state configuration is 2-8-1. 2-7-1-1 indicates that one of electron in ground state got excited by external energy to excited state, and thus, indicates that Na atom is in excited state

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When you add the metal the volume increases from 25.0 to 28.9 how would you find the volume of the metal?
Rzqust [24]

3.9L

Explanation:

Initial volume = 25L

Final volume = 28.9L

The initial volume is the volume of the liquid without the metal in originally in the container. It is 25L

After adding the metal, the volume changes to 28.9L

 Final volume = Initial volume + volume of metal

To find the volume of metal make it the subject of the expression;

    Volume of metal = Final volume - initial volume = 28.9  - 25 = 3.9L

The volume of irregular solids are measured by immersing them in water. The change in volume gives their volume.

Sometimes the volume of water displaced is the volume of the solid.

learn more:

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4 years ago
A 0.4647-g sample of a compound known to contain only carbon, hydrogen, and oxygen was burned in oxygen to yield 0.01962 mol of
Scilla [17]

Answer:

The essence including its given problem is outlined in the following segment on the context..

Explanation:

The given values are:

Moles of CO₂,

x = 0.01962

Moles of water,

\frac{y}{2} =0.01961

y=2\times 0.01961

  =0.03922

Compound's mass,

= 0.4647 g

Let the compound's formula will be:

C_{x}H_{y}O_{z}

Combustion's general equation will be:

⇒  C_{x}H_{y}O_{z}+x+(\frac{y}{4}-\frac{z}{2}) O_{2}=xCO_{2}+\frac{y}{2H_{2}O}

On putting the estimated values, we get

⇒  12\times x=1\times y+16\times z=0.4647

⇒  12\times 0.01962+1\times 0.03922+16\times z=0.4647

⇒  0.27466+16z=0.4647

⇒                     z=0.01187

Now,

x : y : z = 0.01962:0.03922:0.01187

           = \frac{0.01962}{0.0118}:\frac{0.03922}{0.0188}:\frac{0.0188}{0.0188}

           = 1.6:3.3:1.0

           = 3:6:2

So that the empirical formula seems to be "C₃H₆O₂".

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Gold! it's boiling point is 2807 according to this chart:
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