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tatiyna
3 years ago
14

Giving out 15 free pts bc im in a good mood :)

Chemistry
1 answer:
Artemon [7]3 years ago
6 0

Answer:

thank you my friend

Explanation:

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As the ionic compound increases in
Norma-Jean [14]

Given what we know, we can confirm that as an ionic compound grows more complex, its melting point will increase.

<h3>What is an Ionic compound?</h3>
  • An ionic compound is one in which atoms of elements share electrons between them to form compounds.
  • These shared electrons generate powerful electrostatic forces that we refer to as ionic bonds.
  • Electrostatic forces cause an increase in the melting point of a compound.
  • As a compound grows more complex and adds more elements to its composition, it will gain new electrostatic forces, and thus<em><u> increase its melting point.</u></em>

Therefore, as an ionic compound grows more complex, its melting point will increase due to the increasing number of strong electrostatic forces present in the compound.

To learn more about ionic compounds visit:

brainly.com/question/9167977?referrer=searchResults

4 0
3 years ago
Read 2 more answers
Please help I need this
gizmo_the_mogwai [7]
This is going to be a true answer so put true

mark me brainliest
3 0
3 years ago
How are evaporation and condensation related?
natulia [17]
Both evaporation and condensation are in the water cycle. evaporation is when water changes from liquid to gas meanwhile condensation is when water vapor cools and goes from gas to liquid.
8 0
4 years ago
An engineer is investigating the ways in which electroplating is currently
stiks02 [169]

Answer:

Background research

Explanation:

5 0
3 years ago
A solution is prepared by mixing 525 mL of ethanol with 597 mL of water. The molarity of ethanol in the resulting solution is 8.
Alenkinab [10]

Answer:

\Delta V = 234.736\,mL

Explanation:

The quantity of moles of ethanol in the solution is:

n_{C_{2}H_{5}OH} = \left(\frac{597\,mL}{1000\,mL} \right)\cdot \left(8.35\,\frac{mol}{L} \right)

n_{C_{2}H_{5}OH} = 4.985\,mol

The mass and volume of ethanol in the solution are, respectively:

m_{C_{2}H_{5}OH} = (4.985\,mol)\cdot \left(46.07\,\frac{g}{mol} \right)

m_{C_{2}H_{5}OH} = 229.658\,g

V_{C_{2}H_{5}OH} = \frac{229.658\,g}{0.7893\,\frac{g}{mL} }

V_{C_{2}H_{5}OH} = 290.964\,mL

The difference between the total volume of water and ethanol mixed to prepare the solution and the actual volume of solution is:

\Delta V = (525\,mL+597\,mL) - (597\,mL + 290.964\,mL)

\Delta V = 234.736\,mL

8 0
3 years ago
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