1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
natita [175]
3 years ago
11

Introduction:

Chemistry
2 answers:
Alex777 [14]3 years ago
8 0

Answer:

............................................

ki77a [65]3 years ago
8 0

Answer: im not sure if this is the best answer but i wrote, "This exploration is about how the volume of a gas varies with temperature, and what the effect does to the gas and what effect it has on the results."

Explanation: hope this helps.

You might be interested in
Complete these equations for the ionization of an Arrhenius acid or base in water. Include the states of the products.
Mazyrski [523]
1)
 HI(aq) → H⁺(aq) + I⁻(aq)
So this is an Arrhenius acid because it releases H⁺.

2)
LiOH(s) → Li⁺ + OH⁻
So this is an Arrhenius base because it releases OH⁻
3 0
3 years ago
1 2 3 4 5 6 7 8 9 10TIME REMAINING53:56A scientist told his student assistants that he had sorted groups of mice by their intell
Gekata [30.6K]

Answer:

People can introduce their own biases into an experiment.

Explanation:

4 0
2 years ago
I WILL MARK BRAINLIEST How could this sentence be re-written to convey the active voice?
Fed [463]
C is the answer to this question
5 0
3 years ago
Read 2 more answers
A gas of unknown identity diffuses at a rate of 155 mL/s in a diffusion apparatus in which carbon dioxide diffuses at the rate o
Ostrovityanka [42]

Answer:

19.07 g mol^-1

Explanation:

The computation of the molecular mass of the unknown gas is shown below:

As we know that

\frac{Diffusion\ rate\ of unknown\ gas }{CO_{2}\ diffusion\ rate} = \frac{\sqrt{CO_{2\ molar\ mass}} }{\sqrt{Unknown\ gas\ molercular\ mass } }

where,

Diffusion rate of unknown gas = 155 mL/s

CO_2 diffusion rate = 102 mL/s

CO_2 molar mass = 44 g mol^-1

Unknown gas molercualr mass = M_unknown

Now placing these values to the above formula

\frac{155mL/s}{102mL/s} = \frac{\sqrt{44 g mol^{-1}} }{\sqrt{M_{unknown}} } \\\\ 1.519 = \frac{\sqrt{44 g mol^{-1}} }{\sqrt{M_{unknown}} } \\\\ {\sqrt{M_{unknown}} } = \frac{\sqrt{44 g mol^{-1}}}{1.519} \\\\ {\sqrt{M_{unknown}} } = \frac{44 g mol^{-1}}{(1.519)^{2}}

After solving this, the molecular mass of the unknown gas is

= 19.07 g mol^-1

4 0
3 years ago
Please help!!! due soon!
Veseljchak [2.6K]

Answer:

Always stays the same.

7 0
3 years ago
Other questions:
  • Acetic acid is a weak acid with a pKa of 4.76. What is the concentration of acetic acid in a buffer solution of 0.2M at pH 4.9.
    5·1 answer
  • Which of the following provides evidence that supports the continental drift theory? PLEASE HELP 10 POINTS
    14·2 answers
  • How many grams of potassium iodide will produce 500 grams of silver iodide, when there is an excess of silver nitrate?Why?
    6·1 answer
  • Why is water considered "sticky"? What does that mean?
    5·2 answers
  • The normal boiling point corresponds to the temperature at which both the liquid and gas are under the standard atmospheric pres
    6·1 answer
  • What is the electrical power generated from a voltage of 12.3 V if the current is 9.42 amps
    14·1 answer
  • Find the number of moles in 1.00 x 1023 atoms of chromium.
    15·1 answer
  • Which ionization process requires the most energy? which ionization process requires the most energy? f(g) → f +(g) + e- o(g) →
    10·1 answer
  • 2. Tania went outside and made two observations of the Moon that were several days apart. Her
    11·1 answer
  • 2. If a student drops a 2.3 g piece of magnesium into a flask of hydrochloric acid, this reaction occurs: Mg + 2HCl MgCl2 + H2
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!