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Anestetic [448]
3 years ago
10

Consider the combustion of methane (as represented by the following equation). This is the reaction that occurs for a Bunsen bur

ner, which is a source of heat for chemical reactions in the laboratory.
CH4(g) + 2O2(g) →CO2(g) + 2H2O(g)

For the system at chemical equilibrium, which of the following explains what happens if the temperature is raised?

a. The equilibrium is shifted to the right and the value of K increases.
b. The equilibrium is shifted to the right and the value of K decreases.
c. The equilibrium is shifted to the left and the value of K decreases.
d. The equilibrium is shifted to the left and the value of K increases.
e. The equilibrium is shifted but the value of K stays constant.
Chemistry
1 answer:
andre [41]3 years ago
8 0

Answer:

The correct answer is - option C. The equilibrium is shifted to the left and the value of K decreases.

Explanation:

The combustion of the methane produces water vapor, carbon dioxide when burns in presence of oxygen. This reaction also releases heat and light when combustion occurs.

CH4(g) +2O2(g)-----> CO2(g)+ 2H2O(g) + Heat

As this reaction releases the heat which means it is an exothermic reaction and as if the temperature increase, the equilibrium constant decreases, and as it decreases the equilibrium shifted to the left.

Thus, the correct answer is - option C.

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3 years ago
The molarity (M) of an aqueous solution containing 22.5 g of sucrose (C12H22O11) in 35.5 mL of solution is ________.
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Answer:

1.86 M

Explanation:

From the question given above, the following data were obtained:

Mass of sucrose (C12H22O11) = 22.5 g

Volume of solution = 35.5 mL

Molarity of solution =?

Next, we shall determine the number of mole in 22.5 g of sucrose (C12H22O11). This can be obtained as follow:

Mass of sucrose (C12H22O11) = 22.5 g

Molar mass of C12H22O11 = (12×12) + (22×1) + (16×11)

= 144 + 22 + 176

= 342 g/mol

Mole of C12H22O11 =?

Mole = mass /Molar mass

Mole of C12H22O11 = 22.5 /342

Mole of sucrose (C12H22O11) = 0.066 mole

Next, we shall convert 35.5 mL to litres (L). This can be obtained as follow:

1000 mL = 1 L

Therefore,

35.5 mL = 35.5 mL × 1 L / 1000 mL

35.5 mL = 0.0355 L

Thus, 35.5 mL is equivalent to 0.0355 L.

Finally, we shall determine the molarity of the solution as follow:

Mole of sucrose (C12H22O11) = 0.066 mole

Volume of solution = 0.0355 L.

Molarity of solution =?

Molarity = mole /Volume

Molarity of solution = 0.066/0.0355

Molarity of solution = 1.86 M

Therefore, the molarity of the solution is 1.86 M.

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