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kupik [55]
3 years ago
8

Which characteristic influences the polarity of these molecules?

Chemistry
1 answer:
mash [69]3 years ago
4 0

Answer:

The larger the difference in electronegativity, the larger the dipole moment.

Explanation:

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Which statements describe the elements? Which ones are true and which ones are false?
Alchen [17]

Answer:

Explanation:

Uma declaração verdade é identificada pelo de ela afirmar a verdade diferente das outras opções

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3 years ago
It is acceptable to use the seat belt and shoulder harness to secure both the passenger and the wheelchair?
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Suuurre...

If you want to die!!


3 0
3 years ago
An equilibrium mixture of PCl 5 ( g ) , PCl 3 ( g ) , and Cl 2 ( g ) has partial pressures of 217.0 Torr, 13.2 Torr, and 13.2 To
antoniya [11.8K]

Answer: The new partial pressures of PCl_5,PCl_3\text{ and }Cl_2 when equilibrium is re-established are 223.4 torr, 6.82 torr and 26.4 torr respectively.

Explanation:

For the given chemical reaction:

PCl_3(g)+Cl_2(g)\rightleftharpoons PCl_5(g)

The expression of K_p for above reaction follows:

K_p=\frac{P_{PCl_5}}{P_{PCl_3}\times P_{Cl_2}}         ........(1)

We are given:

P_{PCl_5}=217.0torr

P_{PCl_3}=13.2torr

P_{Cl_2}=13.2torr

Putting values in above equation, we get:

K_p=\frac{217.0}{13.2\times 13.2}\\\\K_p=1.24

Now we have to calculate the new partial pressure of Cl_2.

P_{PCl_5}+P_{PCl_3}+P_{Cl_2}=P_{Total}

217.0torr+13.2torr+P_{Cl_2}=263.0torr

P_{Cl_2}=32.8torr

The reaction is re-established and proceed to right direction by Le-Chatelier's principle to cancel the effect of addition of Cl_2.

Now, the equilibrium is shifting to the reactant side. The equation follows:

                       PCl_3(g)+Cl_2(g)\rightleftharpoons PCl_5(g)

Initial:             13.2         32.8            217.0

At eqm:         13.2-x      32.8-x         217.0+x

Putting values in expression 1, we get:

1.24=\frac{(217.0+x)}{(13.2-x)(32.8-x)}\\\\x=40.4,6.38

Neglecting the 40.4 value of 'x'  because pressure can not be more than initial partial pressure.

Thus, the value of 'x' will be, 6.38 torr.

Now we have to calculate the new partial pressures after equilibrium is reestablished.

Partial pressure of PCl_5 = (217.0+x) = (217.0+6.38) = 223.4 torr

Partial pressure of PCl_3 = (13.2-x) = (13.2-6.38) = 6.82 torr

Partial pressure of Cl_2 = (32.8-x) = (32.8-6.38) = 26.4 torr

Hence, the new partial pressures of PCl_5,PCl_3\text{ and }Cl_2 when equilibrium is re-established are 223.4 torr, 6.82 torr and 26.4 torr respectively.

7 0
3 years ago
14. Which of the following is produced when propane (C3H8) is combusted completely? (2 points)
Ymorist [56]

The following is produced when propane (C₃H₈) is combusted completely : H₂O

<h3>Further explanation  </h3>

Complete combustion of Hydrocarbons with Oxygen will be obtained by CO₂ and H₂O compounds.  

If O₂ is insufficient there will be incomplete combustion produced by CO and H and O  

Hydrocarbon combustion reactions (especially alkanes)  \large {\boxed {\bold {C_nH _ (_2_n _ + _ 2_) + \frac {3n + 1} {2} O_2 \Rightarrow nCO_2 + (n + 1) H_2O}}}

For combustion of propane C₃H₈ (n = 3) ⇒ completely(excess O₂) :

C₃H₈+5O₂⇒3CO₂+4H₂O

The products of combustion : CO₂ and H₂O

7 0
3 years ago
I need anyone to answer me.. ​
artcher [175]
A. 2,3
B. 19
C. 28
D. 33
4 0
2 years ago
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