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kupik [55]
3 years ago
8

Which characteristic influences the polarity of these molecules?

Chemistry
1 answer:
mash [69]3 years ago
4 0

Answer:

The larger the difference in electronegativity, the larger the dipole moment.

Explanation:

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How many grams of n2f4 can be produced from 225g f2?
3241004551 [841]
The answer is 615.91 grams of <span>n2f4

Solution:
225g F2 x [(1molF2)/(38gramsF2)] x [</span>(1molF2)/(1molN2F4)] x [(104.02 grams N2F4)/(1molN2F4)]
=615.91 grams
8 0
3 years ago
Many oxidation-reduction reactions can be balanced by inspection. Try to balance the following reactions by inspection. In each
Phoenix [80]

Answer:

Balanced reaction: C₃H₈(g) + 5O₂(g) → 3CO₂(g) + 4H₂O(l)

Reduced: O₂

Oxidized : C₃H₈

Explanation:

For the given reaction:

C₃H₈(g) + O₂(g) → CO₂(g) + H₂O(l)

In the reactants, there are 3 C, and in the products only one, so we multiply CO₂ by 3:

C₃H₈(g) + O₂(g) → 3CO₂(g) + H₂O(l)

In the reactants, there are 8 H, and in the products, there are 2 H, so we multiply H₂O by 4:

C₃H₈(g) + O₂(g) → 3CO₂(g) + 4H₂O(l)

In the reactants are 2 O, and in the products 10 O, so we multiply O₂ by 5:

C₃H₈(g) + 5O₂(g) → 3CO₂(g) + 4H₂O(l)

The reaction is balanced.

Let's identify the oxidation number (Nox) of the elements in each compound.

C₃H₈:

H has fix Nox equal to +1, and the molecule is neutral, so, calling x the Nox of C:

3x + 8 = 0

3x = -8

x = -8/3

O₂:

Because is a pure compound, the Nox of O is 0.

CO₂:

The Nox of O is fix equal to -2, and the molecule is neutral, so, calling x the Nox of C:

2x -4 = 0

2x = 4

x = +2

H₂O:

The Nox of H and O are fixed, respectively, +1 and -2.

So, the carbon in C₃H₈ is oxidized because its Nox is increasing, and oxygen in O₂ is reduced because its Nox is decreasing.

6 0
3 years ago
Why isn't carbon-14 dating accurate for estimating the age of materials older than 50,000 years?
soldi70 [24.7K]
Carbon-14 is radioactive isotope of carbon.
Carbon is essential element of living cells. While the living cells are alive, the carbon contained in them are in equilibrium with the carbon in atmosphere. But, once the cell dies, the carbon-14 isotope undergoes radioactive decay. By measuring the carbon-14 in atmosphere to the carbon-14 in dead organism, we can calculate the time (or years) that organism have died.

However, carbon-14 dating technique is not accurate for estimating the age of materials older than 50,000 years old (above 40,000 years). This is because, 99% of carbon is carbon-12, 1% is carbon-13 and trace remaining is the carbon-14. This means, carbon-14 is found in very trace amount, in fact 1 part per trillion of carbon atoms present is carbon-14. The half of life of carbon-14 is 5,730 years. For dating the organism, we use the concept of half lives of the carbon-14 isotope in the dead organisms and calculate how many half life old the sample is. But as the years increases, the number of carbon-14 isotope becomes too low to detect and make accurate calculation.
This means, at some point the organism can simply run out of carbon-14.

Hence carbon-14 dating is not accurate for estimating age of materials older than 50,000 years old.

5 0
3 years ago
A solution has a<br> pH of 2.5.<br> Answer the following questions.<br> pOH =<br> [H]=<br> [OH]=
Sloan [31]

Answer:

pOH = 11.5

[H⁺] = 0.003 M

[OH⁻] = 3 × 10⁻¹² M

Explanation:

The computation is shown below:

Given that

pH = 2.5

Based on the above information

We know that

pH + pOH = 14  ⇒  pOH = 14 - pH

pOH = 14 - 2.5

pOH = 11.5

[H⁺] = 10^(-pH) = 10^(-2.5)

[H⁺] = 0.003 M

[OH⁻] = 10^(-pOH)

= 10^(-11.5)

= 3 × 10⁻¹² M

[OH⁻] = 3 × 10⁻¹² M

Hence, the above represents the answer

4 0
3 years ago
Part of the solution that is présent in the largest amount is the
xenn [34]

Answer:

The largest amount is called the solvent.

                                 &

The smallest amount is called the solute.

Hope this helps :))

3 0
2 years ago
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