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Ronch [10]
3 years ago
15

You have studied the gas-phase oxidation of HBr by O2: 4 HBr(g) + O2(g) → 2 H2O(g) + 2 Br2(g) You find the reaction to be first

order with respect to HBr and first order with respect to O2. You propose the following mechanism: HBr(g) + O2(g) → HOOBr(g) HOOBr(g) + HBr(g) → 2 HOBr(g) HOBr(g) + HBr(g) → H2O(g) + Br2(g) a. Confirm that the elementary reactions add to give the overall reaction. (Hint: Use Hess Law) b. Based on the experimentally determined rate law, which step is rate determining? c. What are the intermediates in this mechanism? d. If you are unable to detect HOBr or HOOBr among the products, does this disprove your mechanism?

Chemistry
1 answer:
Vlada [557]3 years ago
4 0

Answer:

Explanation:

FIND THE SOLUTION IN THE ATTACHMENT

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Name one solid that can be used in place of candle wax while will give the same result​
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Answer:

Paraffin Wax

Explanation:

Paraffin wax is one of the most widely used waxes for candle making. A cheaper alternative, it is a derivable from petroleum, coal or oil. This wax is white and odorless and will keep a consistent appearance throughout your candle's life.

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Which of the following is NOT a representative particle?<br><br> molecule<br> atom<br> electron
kodGreya [7K]
Answer: Molecule


Step-by-step-explanation
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Suppose 13L of gas is known to contain .965 Mol. If the amount of gas is Increased to 3.20 mol, what new volume will result? (Av
Ostrovityanka [42]

Answer &Explanation:

From Avogadro's lawa equal volume of gas contain equal number of moles

V=N

Hence

13L=965

XL=3.2mol

Hint:as the question state is increase to iteans final mol was 3.2 but if it could state by it would mean initial moles plus adde moles ie 3.2mol)

Cross multiplication

The new volume will be

=(3.2mol×13L÷965mol)

=0.043L

8 0
3 years ago
3- a) write the formula unit of calcium fluoride.
zvonat [6]

Answer:

a) CaF₂.

b) 7.81g of CaF₂ are present.

Explanation:

a) The calcium ion has as charge Ca²⁺ and fluoride ion is F⁻, that means formula unit is:

CaF₂

b) 1 molecule of CaF₂ contains 2 anions, F⁻. Thus, the moles of CaF₂ is:

1.2x10²³ anions * (1 moleculeCaF₂ / 2 anions) = 6x10²² molecules of CaF₂

6.022x10²³ molecules = 1mol:

6x10²² molecules of CaF₂ * (1mol / 6.022x10²³molecules) = 0.10 moles CaF₂.

1 mole of CaF₂ has a mass of 78.07g:

0.10 moles CaF₂ * (78.07g / mol) =

7.81g of CaF₂ are present

5 0
3 years ago
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