Answer: 400K
Explanation:
Given that,
Original volume of balloon V1 = 3.0L
Original temperature of balloonT1 = 27°C
Convert the temperature in Celsius to Kelvin
(27°C + 273 = 300K)
New volume of balloon V2 = 4.0L
New temperature of balloon T2 = ?
Since volume and temperature are given while pressure is constant, apply the formula for Charle's law
V1/T1 = V2/T2
3.0L/300K = 4.0L/T2
To get the value of T2, cross multiply
3.0L x T2 = 4.0L x 300K
3.0LT2 = 1200LK
Divide both sides by 3.0L
3.0LT2/3.0L = 1200LK/3.0L
T2 = 400K
Thus, at a temperature of 400 Kelvin, the balloon would have a volume of 4.0L.
I really don’t know. Sorry
Answer:
It is not possible to determine the type of chemical reaction that will occur when Ca LiOH → without additional information. The chemical formula Ca LiOH could represent a compound, but without knowing what reactants are present and what products are being formed, it is not possible to classify the reaction. Some possible reactions that could occur involving Ca LiOH include a synthesis reaction, where Ca LiOH is formed from its constituent elements, a decomposition reaction, where Ca LiOH breaks down into its constituent elements, or a substitution reaction, where one or more atoms in Ca LiOH are replaced by other atoms.
Explanation:
4 m/s^2
I hope this helps!