Question

Calcium metal reacts in an aqueous solution of nickel(III) sulphate to form calcium sulphate

Answer 1

Answer:

$8.065 * 10^{22}$ atoms of Ca.

Explanation:

Basic stoich question:

First the reaction is $3Ca_{(s)} +Ni_2(SO_4)_{3(aq)} --> 3CaSO_{4(aq)} + 2Ni_{(s)}$

Converting grams to moles: $\frac{5.24g}{58.69g/mol} = 0.0892826 moles.$

Notice the mole ratio. For every 2 Ni produced, 3 Ca was used.

$0.08928267166 moles * \frac{3}{2} = 0.133924 moles$ of Ca.

There are $6.022*10^{23}$ atoms in a mole.

Thus, multiplying them together = $8.065 * 10^{22}$ atoms