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alexandr1967 [171]
4 years ago
10

Suppose you determined the density of a cube to be 1.40 g/cm3. would the density of the cube be different if you had a cube made

of the same material with twice as much mass? explain.
Chemistry
1 answer:
ki77a [65]4 years ago
6 0
Density is mass/volume so if you double the mass you would also double the volume which means density would stay the same. Density is the amount of of matter in a given area and it is constant for the substance regardless of differences in mass or volume.
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A gas sample occupies 3.25 liters at 297.5K and 2.4 atm. Determine the temperature at which the gas will occupy 4.25 L at 1.50 a
lorasvet [3.4K]

For equal moles of  gas, temperature can be calculated from ideal gas equation as follows:

P×V=n×R×T ...... (1)

Initial volume, temperature and pressure of gas is 3.25 L, 297.5 K and 2.4 atm respectively.

2.4 atm ×3.25 L=n×R×297.5 K

Rearranging,

n\times R=0.0262 atm L/K

Similarly at final pressure and volume from equation (1),

1.5 atm ×4.25 L=n×R×T

Putting the value of n×R in above equation,

1.5 atm ×4.25 L=0.0262 (atm L/K)×T

Thus, T=243.32 K


7 0
3 years ago
A farmer uses water to irrigate his potato crops. Which roles of water does this examplify
exis [7]

Answer:

This exemplifies the agricultural role of water.

Explanation:

7 0
3 years ago
Equation 3x-5=-2x+ 10?<br> O<br> 0<br> x= 5<br> -5 = x<br> -15 = -5x<br> -5x = 15
Harman [31]

Answer:

are those the answer choice

7 0
3 years ago
Iron(II) sulfide has a primitive cubic unit cell with sulfide ions at the lattice points.
masya89 [10]

We have that the  the density of FeS  is mathematically given as

  •  \phi=2.56h/cm^3

From the question we are told

Iron(II) sulfide has a primitive <em>cubic</em> unit cell with <em>sulfide</em> ions at the <em>lattice points.</em>

The ionic radii of iron(II) ions and sulfide ions are 88 pm and 184 pm, respectively.

What is the density of FeS (in g/cm3)?

<h3>Density</h3>

Generally the equation for the Velocity  is mathematically given as

V_c=a^3=(2\pi Fe^{2+}+2\pi S^{2-})^3\\\\Therefore\\\\V=a^3(2\pi*0.088+2\pi 0.184)^3\\\\V=16.98*10^{-23}\\\\Therefore\\\\\phi=n\frac{PFeion+PSion}{VNa}\\\\\phi=3*\frac{55.85+32}{16.9*10^{-23}*6.023*10^{23}}

  • \phi=2.56h/cm^3
  • \phi=2.56h/cm^3

For more information on ionic radii visit

brainly.com/question/13981855

4 0
3 years ago
An element from the periodic table is shown below. What can you determine about the number of protons, neutrons, and electrons o
Musya8 [376]

Answer:

They are all the same = 8

Explanation:

Since the symbol of that atom is not give, we can infer from the given number the nature and kind of element we are dealing with.

The number 15.999 rounded up to 16 is the atomic weight of the atom also called the mass number.

Although not peculiar enough, we are certain that this atom is Oxygen.

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For every neutral atom on the periodic table, the number of protons and electrons are the same

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 Number of neutrons = Mass number - atomic number = 16 - 8 = 8

4 0
3 years ago
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