Help plz anyone!?This thing is due 50 points anyone!?
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The feeders in battling machine are represented in proportions and fractions.
- The equation that represents the problem is:
- The feeder can hold <em>30 baseballs</em>, when full
The given parameters are:
<em /><em> ------ 1/6 full</em>
<em /><em> --- baseballs added</em>
<em /><em> ---- 2/3 full</em>
<em />
So, the equation that represents the problem is:
So, we have:
The number of baseballs it can hold is calculated as follows:
Multiply through by 6
Collect like terms
Divide through by 3
Hence, the feeder can hold 30 baseballs, when full
Read more about proportions and fractions at: