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3 years ago

Please help me! I think this 20 character thing is unnecessary when you have an attachment

Mathematics

1 answer:

PIT_PIT [208]3 years ago

8 0

Answer:

Step-by-step explanation:

Also the answer must be under 9 so that rules out option D

Because We know CE = 2 and AD is visibly larger than CE, 6We can rule out option A

And that brings us down to B and C

CB is equal to 6, And I'm no genius, but I'm pretty sure AD is DEFINATLY not equal to 6.

so the answer is B

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What is the value of a?

Annette [7]

Answer:

Step-by-step explanation:

Look at the picture.

The formula of an area of a trapezoid is:

$A=\dfrac{b_1+b_2}{2}\cdot h$

$b_1,\ b_2$ - bases

$h$ - height

We have:

$A=128,\ b_1=a+2,\ b_2=a-2,\ h=8$

Substitute:

$128=\dfrac{a+2+a-2}{2}\cdot8\\\\128=\dfrac{2a}{2}\cdot8$

$128=8a$ <em>divide both sides by 8</em>

$16=a\to a=16$

8 0

3 years ago

Pls help ASAP pls pls pls i will give brainliest if 2 people reply whichever gives best explanation will get brainliset

riadik2000 [5.3K]

Answer:

3 1/3 miles The answer is D

Step-by-step explanation:

The first trip to school is 5/6 miles. Multiply that by 2 because she also walked home and you get 10/6. Then add the distance she she walked to the library- which simplifies to 5/6 and you get 20/6. That simplifies to 3 1/3.

3 0

2 years ago

Read 2 more answers

p varies jointly as q and the square of r, and p = 200 when q = 2 and r = 3. Find p when q = 5 and r= 2.

Margarita [4]

Step-by-step explanation:

If a variables varies jointly, we can just divide it by the other variables in relation to it.

For example, since p variables jointly as q and square of r, then

$\frac{p}{q {r}^{2} } = k$

where k is a constant

First, let find k. Substitute p= 200

q= 2, and r=3.

$\frac{200}{2(3) {}^{2} } = k$

$\frac{200}{18} = k$

$\frac{100}{9} = k$

Now, since we know our constant, let find p.

$\frac{p}{q {r}^{2} } = \frac{100}{9}$

Q is 5, and r is 2.

$\frac{p}{5( {2}^{2}) } = \frac{100}{9}$

$\frac{p}{20} = \frac{100}{9}$

$p = \frac{2000}{9}$

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1 year ago

Factor -12x^6-60x^5-75x^4

lesya [120]

-12x^6 - 60x^5-75x^4.......GCF = 3x^4
3x^4(-4x^2 - 20x - 25)
3x^4(-2x - 5)(2x + 5) <==

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3 years ago

Seven less than the product of 5 and a number is 2

slava [35]

5x-7=2

hope this makes sense

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3 years ago

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