If in the triangle ABC , BF is an angle bisector and ∠ABF=41° then angle m∠BCE=8°.
Given that m∠ABF=41° and BF is an angle bisector.
We are required to find the angle m∠BCE if BF is an angle bisector.
Angle bisector basically divides an angle into two parts.
If BF is an angle bisector then ∠ABF=∠FBC by assuming that the angle is divided into two parts.
In this way ∠ABC=2*∠ABF
∠ABC=2*41
=82°
In ΔECB we got that ∠CEB=90° and ∠ABC=82° and we have to find ∠BCE.
∠BCE+∠CEB+EBC=180 (Sum of all the angles in a triangle is 180°)
∠BCE+90+82=180
∠BCE=180-172
∠BCE=8°
Hence if BF is an angle bisector then angle m∠BCE=8°.
Learn more about angles at brainly.com/question/25716982
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Answer:
99+1
Step-by-step explanation:
Answer:
(2x*+6)(x-2)
2x(x-2)+6(x-2)
2xx+2x(-2)+6x +6(-2)
we know ;
(-). (-) = +
(-). (+) = -
(+). (-) = -
(+). (+) = +
2xx-2x(2)+6x -6(2)
2x^2 - 4x + 6x -12
2x^2 - 2x -12
Step-by-step explanation:
The given equation is an equation of a circle because it looks similar to the general equation of a circle.
<h3>What is the general equation of a circle?</h3>
The general equation of a circle is:
x² + y² +2gx + 2fy + c = 0...........eq1
Where (-g, -f) is the center of the circle.
c is a constant
Given equation is
3x² +6x + 3y²+7y+4 = 0
Let us take 3 as common
x² + 2x+y²+7/3y + 4/3 = 0
Let us rearrange the equation
x² + y²+2x +7/3y + 4/3 = 0...........eq2
Now look at eq1 and eq2
We got that eq2 is having a similar pattern as eq1.
Therefore, The given equation is an equation of a circle.
To get more about circle visit:
brainly.com/question/1506955
