S=56, u=0, v=33, a=?, t=3.4
v=u+at
33=3.4 a
a = 9.7m/s^2
Answer:
The minimum coefficient of friction is 0.666
Explanation:
Suppose, In a classic carnival ride, patrons stand against the wall in a cylindrical shaped room. Once the room gets spinning fast enough, the floor drops from the bottom of the room! Friction between the walls of the room and the people on the ride make them the “stick” to the wall so they do not slide down. In one ride, the radius of the cylindrical room is R = 7.6 m and the room spins with a frequency of 20.9 revolutions per minute.
Given that,
The normal force does not exceed 1.5 times each persons weight

We need to calculate the minimum coefficient of friction
Using balance equation


Where, N = normal force
Put the value into the formula



Hence, The minimum coefficient of friction is 0.666
1 mA = 0.001 A
Therefore, 5 mA = 0.001 * 5
=0.005 A
Resistance = voltage / current
= 100 / 0.005
= 20000 ohms
Current = voltage / resistance
= 25 / 20000
= 0.00125 A (or) 1.25 mA
The word 'apparent' mean in apparent visual magnitude is, how bright the star appears when viewed from Earth.
What is visual magnitude?
The brightness of a celestial body is determined by eye estimation with or without optical aid or by other instrumentation equivalent to the eye in spectral sensitivity.
Apparent magnitude:
- Apparent magnitude is a measure of how bright the star appears when viewed from Earth.
- It is a measure of the brightness of a star or other astronomical object observed from Earth.
- An object's apparent magnitude depends on its intrinsic luminosity and its distance from Earth.
Hence,
The word 'apparent' mean in apparent visual magnitude is, how bright the star appears when viewed from Earth.
Learn more about visual magnitude here:
<u>brainly.com/question/14782876</u>
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Answer:
0.9m/s^2 (yours is 0.87, so choose that)
Explanation:
formula for centripetal acceleration:
v^2/r
to find v, we know that f=1/90s, and r=180m.
v=(2pir)/T
v=(2pi(180))/90
v=12.6m/s
now plug into a=v^2/r
a=(12.6)^2/180
a=0.9m/s^2