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maksim [4K]
3 years ago
10

resistance is inversely proportional to cross sectional area; is it same as cross sectional area inversely proportional to resis

tance?
Physics
1 answer:
mart [117]3 years ago
3 0
The greater the cross sectional area of the condoctor<span>, the greater the number of electrons that move and contribute to the current. Having a larger current for the same </span><span>voltage means having a larger conductance. Since </span>resistance<span> is the </span>inverse<span> of conductance, </span>cross sectional area<span> is </span>inversely related<span> to the </span>resistance<span>.</span>
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Explain why fishes survive in ponds even when the temperature is below 0°c
zmey [24]

Answer:

After sufficient thickness of ice is formed it prevents further loss of heat from the bottom layers of water. This is why fishes and other aquatic animals and plants can survive in ponds and other water bodies even when the atmospheric temperature reaches or is well below 0 degrees.The anomalous expansion of water helps preserve aquatic life during very cold weather. When temperature falls, the top layer of water in a pond contracts becomes denser and sinks to the bottom. ... Thus, even though the upper layer are frozen, the water near the bottom is at 4°C and the fishes can survive in it easily.

3 0
3 years ago
Two foam peanuts become equally charged as they fall out of a cardboard box. Each foam peanut carries a charge of 8 x 10^-4 C. I
jok3333 [9.3K]

Answer:

Answer labeled B : 2,304,000 N

Explanation:

Recall the formula for the electric force:

F_e=9\,\,10^9\,  \,  \frac{q_1*q_2}{d^2} \\F_e=9\,\,10^9\,  \,  \frac{8\,10^{-4}*8\,10^{-4}}{0.05^2} \\F_e=2,304,000\,\,N

which agrees with answer B provided.

7 0
3 years ago
An artillery shell is launched on a flat, horizontal field at an angle of α = 31.7° with respect to the horizontal and with an i
kompoz [17]

Answer:193.90 m/s

Explanation:

Given

launch angle \theta =31.7^{\circ}

launch velocity v_0=202 m/s

Horizontal velocity of the shell after t=18.96 s

time of flight of Projectile T=\frac{2u\sin \theta }{g}

T={\frac2\times 202\sin 31.7}{9.8}

T=21.66 s

i.e. projectile is declining as t>\frac{T}{2}

but horizontal component of velocity will remain same as there is no opposing force in horizontal direction

Horizontal component of velocity is

u_x=v_0\cos \theta =202\cdot \cos 31.7=193.90 m/s  

8 0
3 years ago
Read 2 more answers
According to Newton's first law, an object in motion will stay in motion unless:
Nadusha1986 [10]

Answer: unless it's acted upon by an external force

Explanation: Newton first law of motion State that an object will continue in it state of rest or in motion, unless it is been acted upon by an external force

8 0
3 years ago
A 77.0 kg woman slides down a 42.6 m long waterslide inclined at 42.3. at the bottom, she is moving 20.3 m/s.how much work did f
svlad2 [7]

Answer:

W = 21409.2 J

Explanation:

Given,

The mass of the woman, m = 77 Kg

The length of the water slide, S = 42.6 m

The inclination of the water slide, ∅ = 42.3

The constant velocity of the women sliding, 20.3 m/s

The kinetic friction of the sliding force is given by the formula

                               Fₓ = μₓ η

Where,

                    μₓ - coefficient of kinetic friction

                     η - normal force acting on the body

Since the water slide is inclined at an angle and the person is sliding with constant velocity. The coefficient of friction becomes,

                     μₓ = tan∅

And,                η = mg cos∅

Therefore, the kinetic friction force becomes

                          Fₓ =  tan∅  mg cos∅

Substituting the given values in the above equation

                           Fₓ = 0.9 x 77 x 9.8 x 0,74

                               = 502.56 N

The work done by the kinetic friction on the person

                            W = Fₓ · S    

                                = 502.56 N x 42.6 m

                                = 21409.2 J

Hence, the work done by the friction on the woman is, W = 21409.2 J

8 0
3 years ago
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