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lubasha [3.4K]
3 years ago
10

Now assume that the frictional force f is not at its maximum value. What is the relation between the torque Ï„ applied to each w

heel by the axles and the acceleration a of the car? Once you have the exact expression for the acceleration, make the approximation that the wheels are much lighter than the car as a whole.'
Physics
2 answers:
Kitty [74]3 years ago
8 0

Answer:

The question was dealt with as an incomplete question.

A. The frictional force is in the positive X direction

B. The net force is in the horizontal direction, f is the friction force in each wheel. so the answer is Fnet=4f

C. The weight is distributed equally on each wheel in the Y direction, gives us the formula 4Nwheel-mg=0 with a final answer of N=mg/4

D. torque force at each wheel is tau=rf, linear acceleration is obtained from the sum of the forces 4f=ma, f=tau/r and f=ma/4, (ma/4=tau/r) giving us the final answer of a=4tau/mr (please note that the tau symbol is in the drop down list and looks like a cross between a lowercase r and an upper case T)

leva [86]3 years ago
5 0

Answer:

a)The direction the frictional force will acts is in the positive x direction.

Explanation:

a)The direction the frictional force will acts is in the positive x direction

b)in the horizontal direction, the total force F(total) is equal to 4times the frictional force in the wheel.

F(total)=4f

''f'' is taken as the frictional force.

c)4times the normal force on each wheel minus the acceleration equals zero i.e 4N(wheel)-a=0

=4N(wheel)-mg=0

d) torque is the force that tends to bend rotation

ζ=rf

but acceleration=4×frictional force

cross multiply

f=ζ/r

f=ma/4

ma/4=ζ/r

a=4ζ/r

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Answer:

Thorium 227 (also known as Radioactinium)

5 0
2 years ago
During a very quick stop, a car decelerates at 7.6 m/s2. Assume the forward motion of the car corresponds to a positive directio
Mashcka [7]

Answer:

24.57 revolutions

Explanation:

(a) If they do not slip on the pavement, then the angular acceleration is

\alpha = a / r = 7.6 / 0.26 = 29.23 rad/s^2

(b) We can use the following equation of motion to find out the angle traveled by the wheel before coming to rest:

\omega^2 - \omega_0^2 = 2\alpha\Delta \theta

where v = 0 m/s is the final angular velocity of the wheel when it stops, \omega_0 = 95rad/s is the initial angular velocity of the wheel, \alpha = -29.23 rad/s^2 is the deceleration of the wheel, and \Delta \theta is the angle swept in rad, which we care looking for:

0 - 95^2 = 2*29.23\Delta \theta

9025 = 58.46 \Delta \theta

\Delta \theta = 9025 / 58.46 = 154.375 rad

As each revolution equals to 2π, the total revolution it makes before stop is

154.375 / 2π = 24.57 revolutions

8 0
2 years ago
1.what is gravity?(in your own words)
olga_2 [115]

Answer:

1.Gravity is an invisible force that pulls objects toward each other

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hope it helped:)

8 0
2 years ago
A worker drops a wrench from the top of a tower 80m tall. What is the velocity when the
OlgaM077 [116]

Answer:

39.6 m/s

Explanation:

Taking down to be positive:

Given:

v₀ = 0 m/s

a = 9.8 m/s²

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v² = (0 m/s)² + 2 (9.8 m/s²) (80 m)

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3 0
3 years ago
A car travels 36 km in 30 minutes. The speed of the car is
iogann1982 [59]

Answer:

72km/hr

Explanation:

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so the speed of the car is 72km/hr

7 0
3 years ago
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