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3 years ago

Anybody help me? my H.W. Q 14-17 thank you, please show work

Physics

1 answer:

Kipish [7]3 years ago

4 0

14. Reactants:

Magnesium Chloride: $Mg Cl_2$ , since magnesium (Mg) has 2 valence electrons while chlorine (Cl) has 1 vacancy, so they are in ratio 1:2

Sodium oxide: $Na_2 O$ , since sodium (Na) has 1 valence electron while oxygen (O) has 2 vacancies, so they are in ratio 2:1

15. Products:

Magnesium oxide: $Mg O$ , since magnesium (Mg) has 2 valence electrons and oxygen (O) has 2 vacancies, so they are in ratio 1:1

Sodium chloride: $NaCl$ , since sodium (Na) has 1 valence electron and chlorine (Cl) has 1 vacancy, so they are in ratio 1:1

16: Balanced reaction:

$Mg Cl_2 + Na_2 O \rightarrow Mg O+2NaCl$

we see that on the reactant side we have: 1 atom of Mg, 2 atoms of Cl, 2 atoms of Na and 1 atom of O. By putting a 2 in front of NaCl, we have exactly the same on the product side: 1 atom of Mg, 2 atoms of Cl, 2 atoms of Na and 1 atom of O.

17. It is a double-replacement reaction

A double-replacement reaction occurs when two ionic compounds exchange their ions. In this specific case, we see that the Chlorine (initially bond with the magnesium) is then bond with the sodium, while the oxygen (initially bond with the sodium) after the reaction is bond with the magnesium.

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3 years ago

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3 years ago

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Bambi the young dear was distracted Buy butterfly and jumped into the road in front of the two vehicles as shown in the diagram

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Speed of car A is given as

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now we need to convert it into SI units

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1 hour = 3600 s

now we have

$v_a = 70 *\frac{1609}{3600} = 31.3 m/s$

now its distance from Bambi is given as

$d_a = 350 m$

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$v_b = 22.35 m/s$

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3 years ago

A 23.5 g piece of aluminum metal is initially at 100.0°C. It is dropped into a coffee cup-calorimeter containing 130.0 g of wate

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Answer: The molar heat capacity of aluminum is $25.3J/mol^0C$

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$m_1\times c_1\times (T_{final}-T_1)=-[m_2\times c_2\times (T_{final}-T_2)]$ .................(1)

where,

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$T_1$ = temperature of water = $23^oC=(273+23)K=296K$

$T_2$ = temperature of aluminium = $100^oC=273+100=373K$

$c_1$ = specific heat of water= $4.184J/g^0C$

$c_2$ = specific heat of aluminium= ?

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$c_2=0.938J/g^0C$

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Thus molar heat capacity = $0.938J/g^0C\times 27g/mol=25.3J/mol^0C$

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3 years ago

Anybody help me? my H.W. Q 14-17 thank you, please show work​

Anybody help me? my H.W. Q 14-17 thank you, please show work