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3 years ago

Anybody help me? my H.W. Q 14-17 thank you, please show work

Physics

1 answer:

Kipish [7]3 years ago

4 0

14. Reactants:

Magnesium Chloride: $Mg Cl_2$ , since magnesium (Mg) has 2 valence electrons while chlorine (Cl) has 1 vacancy, so they are in ratio 1:2

Sodium oxide: $Na_2 O$ , since sodium (Na) has 1 valence electron while oxygen (O) has 2 vacancies, so they are in ratio 2:1

15. Products:

Magnesium oxide: $Mg O$ , since magnesium (Mg) has 2 valence electrons and oxygen (O) has 2 vacancies, so they are in ratio 1:1

Sodium chloride: $NaCl$ , since sodium (Na) has 1 valence electron and chlorine (Cl) has 1 vacancy, so they are in ratio 1:1

16: Balanced reaction:

$Mg Cl_2 + Na_2 O \rightarrow Mg O+2NaCl$

we see that on the reactant side we have: 1 atom of Mg, 2 atoms of Cl, 2 atoms of Na and 1 atom of O. By putting a 2 in front of NaCl, we have exactly the same on the product side: 1 atom of Mg, 2 atoms of Cl, 2 atoms of Na and 1 atom of O.

17. It is a double-replacement reaction

A double-replacement reaction occurs when two ionic compounds exchange their ions. In this specific case, we see that the Chlorine (initially bond with the magnesium) is then bond with the sodium, while the oxygen (initially bond with the sodium) after the reaction is bond with the magnesium.

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A light bulb is rated at 25 W when operated at 120 V. How much charge enters (and leaves) the light bulb in 1. 0 min?

aleksklad [387]

The amount of charge enters (and leaves) is 12 Coulomb.

<h3 /><h3>How can we find the value of the amount of charge enters (and leaves)?</h3>

Here we are using the formula,

$I=\frac{P}{V}$ and $Q= I \times t$

We are given,

P = Power of the light bulb = 25 Watt.

V = The amount of voltage where the light bulb operated = 120 Volt.

t= The time when charge enters (and leaves) the light bulb = 1.0 min = $(1 \times 60) second$ = 60 S

We have to find,

I= The amount of current flows in the light bulb.

Q= The amount of charge enters (and leaves) the light bulb.

Now we substitute the values of known parameters in the first equation, we find that,

$I=\frac{P}{V}=\frac{25}{120}$

Or, $I= 0.20 A$

The amount of current flows in the light bulb is 0.20 Ampere.

Now, we put the value of I in the second equation,

$Q= I \times t= 0.20 \times 60$

Or, $Q=12 C$

So, from the above calculations we can see that the amount of charge enters (and leaves) the light bulb is 12 Coulomb.

Learn more about the light bulb:

brainly.com/question/8979272

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2 years ago

A battery establishes a voltage V on a parallel-plate capacitor. After the battery is disconnected, the distance between the pla

Semmy [17]

Answer:

In the parallel plate capacitor

The capacitance will decrease between the plates.

The voltage will increase between the plates.

Explanation:

When the distance between the plates increase, then the voltage also increases as it varies with the separation of plates. However the capacitance will decrease upon increasing the distance. As the capacitance depends upon the electric field between the plates. Field is stronger when the plates are closer so capacitance increase. Field will be weaker upon increasing the distance and hence the capacitance decreases.

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3 years ago

An Olympic diver springs off of a high dive that is 3 m above the surface of the water. When she lands in the water she is trave

klemol [59]

Answer: $u=4.51 m/s\ at\ angle\ of\ \theta =59.34^{\circ}$

Explanation:

Given

height of building h=3 m

Landing velocity of diver $v=8.90 m/s$ at an angle of $75^{\circ}$

Let u be the initial velocity of diver at an angle of \theta with horizontal

Since there is no acceleration in horizontal direction therefore horizontal component of velocity will remain same

$u\cos \theta =8.9\cos (75)$ ---- -----1

Considering Vertical motion

$v^2-u^2=2as$

here $v=8.9\sin (75)$

$u=u\sin \theta$

$s=3 m$

$a=9.8 m/s^2$

$(8.9\sin (75))^2-(u\sin \theta )^2=2\times 9.8\times 3$

$u\sin \theta =\sqrt{(8.9\sin 75)^2-(2\cdot 9.8\cdot 3)}$

$u\sin \theta =3.886$ ----------------2

Divide 2 and 1 we get

$\tan \theta =\frac{3.886}{8.9\cos (75)}$

$\tan \theta =1.687$

$\theta =59.34^{\circ}$

Thus $u\cos (59.34)=8.9\cos (75)$

$u=4.51 m/s$

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3 years ago

Which of the following expenses will most likely be the most expensive?

Jlenok [28]

Option B makes the most sense. Option A is something you acquire, it wouldn't really cost anything. Utilities usually do not cost more than housing. Savings are subjective, dependent on the person. So option B.
Hope it helps!

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3 years ago

Find the electric flux passing through the 45° surface of an upright circular cone with a base diameter of 4 m if the electric f

alexgriva [62]

Answer:

electric flux = 177.625 N-m²/C

Explanation:

given data

angle = 45°

diameter = 4 m

electric field E = 20 N/C

to find out

electric flux

solution

we know electric flux formula that is

electric flux = E × A × cosθ ..............1

here A is area that is

Area = πd²/4 = π(4)²/4 = 12.56 m²

now put all value in equation 1

electric flux = 20 × 12.56 × cos45

electric flux = 177.625 N-m²/C

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3 years ago

Anybody help me? my H.W. Q 14-17 thank you, please show work​

Anybody help me? my H.W. Q 14-17 thank you, please show work