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alexdok [17]
2 years ago
8

23. What is the distance between the points (3, 4) and (3,-7)?

Mathematics
1 answer:
Neko [114]2 years ago
6 0

Answer:

11

Step-by-step explanation:

Since both points have the same x value, we know they are vertical to each other.

One point is 4 units above the x axis, the other is 7 below the x axis.

4 + 7 = 11

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3 years ago
What basic trigonometric identity would you use to verify that (sin2x + cos2x)/cosx=secx
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2 years ago
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Write the least common denominator for 2/3, 4/5, and 5/6.
Lunna [17]

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30 I think but I'm probably wrong

5 0
2 years ago
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Write the equation of the line that contains the points (4, −7) and (1, 5). The slope of the line that contains the points (4, −
deff fn [24]
Slope = (5+7)/(1-4) = 12/-3 = -4

slope = -4

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equation
y = -4x + 9
4 0
2 years ago
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Inequality to x2 &lt; 64
Anarel [89]
              NOT MY WORDS TAKEN FROM A SOURCE!

(x^2) <64  => (x^2) -64 < 64-64 => (x^2) - 64 < 0 64= 8^2    so    (x^2) - (8^2) < 0  To solve the inequality we first find the roots (values of x that make (x^2) - (8^2) = 0 ) Note that if we can express (x^2) - (y^2) as (x-y)* (x+y)  You can work backwards and verify this is true. so let's set (x^2) - (8^2)  equal to zero to find the roots: (x^2) - (8^2) = 0   => (x-8)*(x+8) = 0       if x-8 = 0 => x=8      and if x+8 = 0 => x=-8 So x= +/-8 are the roots of x^2) - (8^2)Now you need to pick any x values less than -8 (the smaller root) , one x value between -8 and +8 (the two roots), and one x value greater than 8 (the greater root) and see if the sign is positive or negative. 1) Let's pick -10 (which is smaller than -8). If x=-10, then (x^2) - (8^2) = 100-64 = 36>0  so it is positive
2) Let's pick 0 (which is greater than -8, larger than 8). If x=0, then (x^2) - (8^2) = 0-64 = -64 <0  so it is negative3) Let's pick +10 (which is greater than 10). If x=-10, then (x^2) - (8^2) = 100-64 = 36>0  so it is positive Since we are interested in (x^2) - 64 < 0, then x should be between -8 and positive 8. So  -8<x<8 Note: If you choose any number outside this range for x, and square it it will be greater than 64 and so it is not valid.

Hope this helped!

:)
7 0
2 years ago
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