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alexdok [17]
3 years ago
8

23. What is the distance between the points (3, 4) and (3,-7)?

Mathematics
1 answer:
Neko [114]3 years ago
6 0

Answer:

11

Step-by-step explanation:

Since both points have the same x value, we know they are vertical to each other.

One point is 4 units above the x axis, the other is 7 below the x axis.

4 + 7 = 11

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What is the perimeter of a polygon with vertices at (−2, 1) , ​ (−2, 4) ​, (2, 7) , ​ (6, 4) ​, and (6, 1) ​?
alekssr [168]
First we need the distances of the sides of the polygon, because perimeter = sum of all sides.
d =  \sqrt{{(y2 - y1)}^{2} + {(x2 - x1)}^{2} }
d1 =  \sqrt{{(1 - 4)}^{2} + {( - 2 -  - 2)}^{2} } \\  =  \sqrt{{(- 3)}^{2} + {(0)}^{2} } =  \sqrt{9}  \: = 3
d2 = \sqrt{{(4 - 7)}^{2} + {( - 2 - 2)}^{2} } \\  = \sqrt{{(- 3)}^{2} + {( -4)}^{2} } =  \sqrt{9 + 16}  \\  =  \sqrt{25}  \: = 5
d3 \: = \sqrt{{(7 - 4)}^{2} + {(2 - 6)}^{2} } \\  =  \sqrt{{(3)}^{2} +  {( - 4)}^{2} } =  \sqrt{9 + 16}  \\  =  \sqrt{25} \:  = 5
d4 = \sqrt{{(4 - 1)}^{2} + {(6 - 6)}^{2} } \\  =  \sqrt{ {(3)}^{2} +  {(0)}^{2}  }  =  \sqrt{9} \:  = 3
d5 = \sqrt{{(1 - 1)}^{2} + {(-2 - 6)}^{2} }  \\ =  \sqrt{ {(0)}^{2} +  {( - 4)}^{2}} =  \sqrt{16}  \:  = 4
Now, we add all sides for the perimeter:
p = d1 + d2 + d3 + d4 + d5
p = 3+5+5+3+4 = 20 units





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Answer:

its a lot u'll see at the end

Step-by-step explanation:

a) 4n = 4,8,12,16,20

b) 2n+1= 3,5,7,9,11

c) 3n-2= 1,4,7,10,13

d) 1÷2n+1= \frac{3}{2}, \frac{5}{4} ,\frac{7}{6} ,\frac{9}{8} ,\frac{11}{10} ,

e) 20-5n= 15,10,5,0,-5

f) -2n+3= 1,-1,-3,-5,-7

took me a while hope it is helpful

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ioda

Answer: C

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Nonlinear association

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