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alexdok [17]
2 years ago
8

23. What is the distance between the points (3, 4) and (3,-7)?

Mathematics
1 answer:
Neko [114]2 years ago
6 0

Answer:

11

Step-by-step explanation:

Since both points have the same x value, we know they are vertical to each other.

One point is 4 units above the x axis, the other is 7 below the x axis.

4 + 7 = 11

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(ab - 9)(ab + 8)<br> please simplify for me
Ahat [919]

1. Use the FOIL method: (a+b)(c+d)=ac+ad+bc+bd(a+b)(c+d)=ac+ad+bc+bd(a+b)(c+d)=ac+ad+bc+bd

a​^2​​b​^2​​+8ab−9ab−72

2. Collect the like terms

a^2b^2+(8ab−9ab)−72

3. Simplify

a^2b^2-ab-72

Hope this helps




5 0
3 years ago
Pllllllllllllllllllllleasee one guys i neeed ur help one
Svetllana [295]

{ \qquad\qquad\huge\underline{{\sf Answer}}}

Let's solve ~

Calculate discriminant :

\qquad \sf  \dashrightarrow \: 3 {x}^{2}  + 6x - 1

  • a = 3
  • b = 6
  • c = 1

\qquad \sf  \dashrightarrow \: discriminant =  {b}^{2}  - 4ac

\qquad \sf  \dashrightarrow \: d = (6) {}^{2}  - (4 \times 3 \times 1)

\qquad \sf  \dashrightarrow \: d = 36 - 12

\qquad \sf  \dashrightarrow \: d = 24

\qquad \sf  \dashrightarrow \:  \sqrt {d} = 2 \sqrt{6}

Now, let's calculate it's roots ( x - intercepts )

\qquad \sf  \dashrightarrow \: x =  \cfrac{ - b  \pm \sqrt{d} }{2a}

\qquad \sf  \dashrightarrow \: x =  \cfrac{ - 6\pm 2 \sqrt{6}  }{2 \times 3}

\qquad \sf  \dashrightarrow \: x =  \cfrac{ - 6\pm 2 \sqrt{6}  }{6}

So, the intercepts are :

\qquad \sf  \dashrightarrow \: x =  \cfrac{ - 6 -  2 \sqrt{6}  }{6}

and

\qquad \sf  \dashrightarrow \: x =  \cfrac{ - 6  +  2 \sqrt{6}  }{6}

5 0
1 year ago
Read 2 more answers
In a rectangular coordinate plane what is the distance between points (-3,0) and (3,8)
zheka24 [161]

To calculate the distance between two points, we can use a formula that is a variation Pythagorean Theorem. Look:


\mathsf{d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}}


"d" represents the distance and coordinates are expressed as follows: (x, y)


Let's go to the calculations.


\mathsf{d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}}\\\\ \mathsf{d=\sqrt{(3-(-3))^2+(8-0)^2}}\\\\ \mathsf{d=\sqrt{(3+3)^2+(8)^2}}\\\\ \mathsf{d=\sqrt{(6)^2+64}}\\\\ \mathsf{d=\sqrt{36+64}}\\\\ \mathsf{d=\sqrt{100}}\\\\ \underline{\mathsf{d=10}}


The answer is 10 uc.

8 0
3 years ago
What number goes on top and how do you solve it.
vekshin1
So basically, each number is equal to the two numbers below it added together.

See, 7 = 3+4, 8 = 5 +3, etc.

So, the top would be 16 + 17.

16 + 17 = 33

So 33 goes on top.
4 0
3 years ago
A multiple choice test consists of six questions, each of which has four choices. Each question has exactly one correct answer.
mario62 [17]
To get 4 or fewer correct, at least 2 answers have to be wrong. And the probability of that is:
3/4 x 3/4=9/16
1-9/16=probability that 4 or fewer are correct=7/16 ☺☺☺☺
6 0
3 years ago
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