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4 years ago

Write the inequality shown by the shaded area

Mathematics

1 answer:

Sladkaya [172]4 years ago

4 0

Answer: y≤ $\frac{7}{3}x+2$

Step-by-step explanation:

Since we are given the equation, all we have to do is to fix the inequality. We have four options: <, >, ≤, and ≥. The line in the graph is a solid line. This means the line reaches and is equal to the points on the line. We can automatically eliminate ≤ and ≥. Now, we know the answer is ≤. The shading shows that the answer is less than 7/3x+2. In other words, y≤ $\frac{7}{3} x+2$ .

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What’s number 12 through 15 pls I need this ASAP

galben [10]

Answer:

12. 9

Step-by-step explanation:

12. Using Pythagoras theorem

let shortest distance be = x

8 square + 5 square = x square

64 + 25 = x square

89 = x square

Therefore x = square root of 89

Thus X = 9

8 0

3 years ago

What’s the answer? Pls help soon

Vilka [71]

You get this or no??

6 0

3 years ago

Read 2 more answers

What is the area of a regular nonagon (9 sides) with side length of 15 cm and apothem of 20.6 cm? Round the answer to the neares

Triss [41]

We know that

<span>The nine radii of a regular Nonagon divides into 9 congruent isosceles triangles
</span>therefore
[the area of <span>a regular nonagon]=9*[area of isosceles triangle]

</span>[area of isosceles triangle]=b*h/2------> 15*20.6/2----> 154.5 cm²
so
[the area of a regular nonagon]=9*[154.5]------> 1390.5 cm²

the answer is
1390.5 cm²

5 0

3 years ago

The triangular entrance to a tent is 2/3 as wide as it is tall. The area of the entrance is 12ft^2. Find the height and the base

Reika [66]

X+ $\frac{2}{3} x$ =12
5x=36
x=7.2
So, the triangular entrance to the tent is 7.2 feet tall and 4.8 feet wide

4 0

3 years ago

Type the correct answer in each box. If necessary, round your answers to the nearest hundredth.

disa [49]

Answer:

Perimeter = 32.44 units

Area = 30 square units

Step-by-step explanation:

Given

Vertices

A(2,8), B(16,2) and C(6,2)

WE have to determine the lengths of all sides before finding the perimeter and area.

The formula of modulus is:

$d = \sqrt{(x_{2}- x_{1})^{2} +(y_{2}-y_{1})^{2}}\\AB=\sqrt{(16-2)^{2} +(2-8)^{2}}\\=\sqrt{(14)^{2} +(-6)^{2}}\\=\sqrt{196+36}\\ =\sqrt{232}\\=15.23\\\\BC=\sqrt{(6-16)^{2} +(2-2)^{2}}\\=\sqrt{(-10)^{2} +(0)^{2}}\\=\sqrt{100+0}\\ =\sqrt{100}\\=10\\\\AC=\sqrt{(6-2)^{2} +(2-8)^{2}}\\=\sqrt{(4)^{2} +(-6)^{2}}\\=\sqrt{16+36}\\ =\sqrt{52}\\=7.21\\\\$

So the perimeter is:

$Perimeter=AB+BC+AC\\=15.23+10+7.21\\=32.44\ units$

Using hero's formula,

$s=\frac{perimeter}{2}\\s=\frac{32.44}{2}\\ s=16.22\\Area=\sqrt{s(s-a)(s-b)(s-c)}\\=\sqrt{16.22(16.22-15.23)(16.22-10)(16.22-7.21)}\\=\sqrt{(16.22)(0.99)(6.22)(9.01)}\\=\sqrt{899.91}\\=29.99\ square\ units$

Rounding off will give us 30 square units ..

4 0

4 years ago