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Nataly [62]
3 years ago
11

You know that there are 1,609 meters in a mile. The number of feet in a mile is 5,280. Use these equalities to

Physics
1 answer:
ElenaW [278]3 years ago
6 0
Part a).

You said that    1,609 meters = 5,280 feet

We know that 1 meter = 100 centimeters, and 1 foot = 12 inches.

So  (1,609 meters) x (100 centimeters/meter)  =  (5,280 feet) x (12 inches/foot)

The second fraction on each side of the equation is equal to ' 1 ', because
the numerator is equal to the denominator, so sticking it in there doesn't
change the value of that side of the equation.  But now we can cancel some
units,and wind up with the units we need.

   (1,609 meters) x (100 centimeters/meter)  =  (5,280 feet) x (12 inches/foot)

         (1,609 x100) centimeters  =  (5,280 x 12) inches

             160,900 centimeters  =  63,360 inches

Divide each side by  63,360 :        <em> 2.54 centimeters =  1 inch</em>

=================================
part b).

I haven't seen the snail, or anything else in problem 7,
so there's no way I can answer this part.

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Answer:

A. Increasing the voltage of the battery

Explanation:

The relationship between voltage, V, current, I and resistance, R, is given as follows;

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A force of 45 N is applied tangentially to the rim of a solid disk of radius 0.12 m. The disk rotates about an axis through its
bearhunter [10]

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Mass of the disk will be 2.976 kg

Explanation:

We have given force F = 45 N

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We know that torque \tau =I\alpha

And \tau =Fr

So Fr=I\alpha , here I is moment of inertia

So 50\times 0.12=I\times 140

I=0.0428kgm^2

We know that moment of inertia I=\frac{1}{2}mr^2

So 0.0428=\frac{1}{2}\times m\times 0.12^2

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A satellite completes one revolution of a planet in almost exactly one hour. At the end of one hour, the satellite has traveled
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A 4-79 permalloy solenoid coil needs to produce a minimum inductance of 1.1 . If the maximum allowed current is 4 , how many tur
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The related concept to solve this exercise is given in the expressions that the magnetic field has both as a function of the number of loops, current and length, as well as inductance and permeability. The first expression could be given as,

The magnetic field H is given as,

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Here,

n = Number of turns of the coil

I = Current that flows in the coil

l = Length of the coil

From the above equation, the number of turns of the coil is,

n = \frac{Hl}{I}

The magnetic field is again given by,

H = \frac{B}{\mu_t}

Where the minimum inductance produced by the solenoid coil is B.

We have to obtain n, that

n = \dfrac{\frac{B}{\mu_t}l}{I}

Replacing with our values we have that,

n = \dfrac{\frac{1.1Wb/m^2 }{200000}(2m)}{4mA}

n = \dfrac{(\frac{1.1Wb/m^2 }{200000})(\frac{10^4 guass}{1Wb/m^2})(2m)}{4mA(\frac{10^{-3}A}{1mA})}

n = 27.5 \approx 28

Therefore the number of turn required is 28Truns

4 0
4 years ago
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