1.concave lens

Closed clusters are groups of closely grouped stars that are located along the spiral disk of a galaxy.

Gre4nikov [31]

<span>False. Closed clusters are groups of closely grouped stars located in the halo of a galaxy, not along the spiral disk. Open clusters are groups of loosely associated stars located along the spiral disk of a younger galaxy with active star formation.</span>

5 0

3 years ago

The Sun delivers an average power of 1150 W/m2 to the top of the Earth’s atmosphere. The permeability of free space is 4π × 10−7

My name is Ann [436]

Answer:

E=930.84 N/C

Explanation:

Given that

I = 1150 W/m²

μ = 4Π x 10⁻⁷

C = 2.999 x 10⁸ m/s

E= C B

C=speed of light

B=Magnetic filed ,E=Electric filed

Power P = I A

A=Area=4πr² ,I=Intensity

$I=\dfrac{CB^2}{2\mu_0}$

$I=\dfrac{CE^2}{2\mu_0 C^2}$

$E=\sqrt{{2I\mu_0 C}}$

$E=\sqrt{{2\times 1150\times 4\pi \times 10^{-7}(2.99792\times 10^8)}}$

E=930.84 N/C

Therefore answer is 930.84 N/C

4 0

4 years ago

I HAVE A PHYSICS TEST, ITS 25 QUESTIONS AND I HAVE ABOUT AN HOUR TO SOLVE IT. PLEASE IF YOU’RE GOOD AT PHYSICS CONTACT ME ASAP

Katena32 [7]

Answer:

in which Class u studying

5 0

3 years ago

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In the far future, astronauts travel to the planet Saturn and land on Mimas, one of its 62 moons. Mimas is small compared with t

Mamont248 [21]

Answer:

a) $h_{max}=14536.16 m$

b) $h = 15687.9 m$

c) $PD=7.62\%$ The estimate is low.

Explanation:

a) Using the energy conservation we have:

$E_{initial}=E_{final}$

we have kinetic energy intially and gravitational potential energy at the maximum height.

$\frac{1}{2}mv^{2}=mgh_{max}$

$h_{max}=\frac{v^{2}}{2g}$

$h_{max}=\frac{43^{2}}{2*0.0636}$

$h_{max}=14536.16 m$

b) We can use the equation of the gravitational force

$F=G\frac{mM}{R^{2}}$ (1)

We have that:

$F = ma$ (2)

at the surface G will be:

$G=\frac{gR^{2}}{M}$

Now the equation of an object at a distance x from the surface.

is:

$F=\frac{mgR^{2}}{(R+x)^{2}}$

$m\frac{dv}{dt}=\frac{mgR^{2}}{(R+x)^{2}}$

Using that dv/dt is vdx/dt and integrating in both sides we have:

$v_{0}=\sqrt{\frac{2gRh}{R+h}}$

$h=\frac{v_{0}^{2}R}{2gR-v_{0}^{2}}$

$h=15687.9$

c) The difference is:

So the percent difference will be:

$PD=|\frac{14536.16-15687.9}{(14536.16+15687.9)/2}*100%$

$PD=7.62\%$

The estimate is low.

I hope it helps you!

7 0

3 years ago

Which scenario would be classified as a conceptual model

den301095 [7]

Answer:

Heyo! (Ish Mash Potato) XD

Explanation:

A conceptual model is a representation of a system, made of the composition of concepts which are used to help people know, understand, or simulate a subject the model represents. It is also a set of concepts. Some models are physical objects; for example, a toy model which may be assembled, and may be made to work like the object it represents.

Hope Mr. Mash Potato Helped!!!

3 0

3 years ago

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