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Temka [501]
3 years ago
7

In ΔABC, if m∠A = 43° and m∠C = 66°, then find m∠B.

Mathematics
1 answer:
weqwewe [10]3 years ago
6 0
The measures of the angles in a triangle add up to 180°.
m \angle A + m \angle B + m \angle C = 180^\circ \\
m \angle A=43^\circ, \ m \angle C = 66^\circ \\ \downarrow \\
43^\circ+ m \angle B + 66^\circ = 180^\circ \\
m \angle B + 109^\circ = 180^\circ \\
m \angle B =180^\circ - 109^\circ \\
\boxed{m \angle B=71^\circ}
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Which of the following expressions are equivalent to x−(−x)+y
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C.  None of the above.

Step-by-step explanation:

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Which equation is a quadratic model for the data set? Hint: Use a graphing calculator or a spreadsheet program.
Ivahew [28]

The equation that model a quadratic function is:  y=0.9673x²-0.8475x+10.4334

Step-by-step explanation:

A quadratic function has the form of ;

f(x) = ax²+bx+c  where a, b and c are real numbers and a≠0

For this case, equation y=0.9673x²-0.8475x+10.4334 models a quadratic function where a>0 thus the parabola opens upwards

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Quadratic functions graphs: brainly.com/question/9048896

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4 0
3 years ago
What is the factorization of 729^15+1000?
igomit [66]

Answer:

The factorization of 729x^{15} +1000 is (9x^{5} +10)(81x^{10} -90x^{5} +100)

Step-by-step explanation:

This is a case of factorization by <em>sum and difference of cubes</em>, this type of factorization applies only in binomials of the form (a^{3} +b^{3} ) or (a^{3} -b^{3}). It is easy to recognize because the coefficients of the terms are <u><em>perfect cube numbers</em></u> (which means numbers that have exact cubic root, such as 1, 8, 27, 64, 125, 216, 343, 512, 729, 1000, etc.) and the exponents of the letters a and b are multiples of three (such as 3, 6, 9, 12, 15, 18, etc.).

Let's solve the factorization of 729x^{15} +1000 by using the <em>sum and difference of cubes </em>factorization.

1.) We calculate the cubic root of each term in the equation 729x^{15} +1000, and the exponent of the letter x is divided by 3.

\sqrt[3]{729x^{15}} =9x^{5}

1000=10^{3} then \sqrt[3]{10^{3}} =10

So, we got that

729x^{15} +1000=(9x^{5})^{3} + (10)^{3} which has the form of (a^{3} +b^{3} ) which means is a <em>sum of cubes.</em>

<em>Sum of cubes</em>

(a^{3} +b^{3} )=(a+b)(a^{2} -ab+b^{2})

with a= 9x^{5} y b=10

2.) Solving the sum of cubes.

(9x^{5})^{3} + (10)^{3}=(9x^{5} +10)((9x^{5})^{2}-(9x^{5})(10)+10^{2} )

(9x^{5})^{3} + (10)^{3}=(9x^{5} +10)(81x^{10}-90x^{5}+100)

.

8 0
2 years ago
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