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Llana [10]
3 years ago
6

A person's body is covered with 1.69 m^2 of wool clothing. The thickness of the wool is 1.87 × 10^-3 m. The temperature at the o

utside surface of the wool is 13.9 °C, and the skin temperature is 35.4 °C. How much heat per second does the person lose due to conduction?
Physics
1 answer:
gayaneshka [121]3 years ago
6 0

The concept required to solve this problem is related to heat conductivity as a function of time.

Mathematically in a stable state the heat flux is constant and its rate of change as a function of time can be described under the function

\frac{Q}{t} = \frac{kA\Delta T}{d}

Where

k= Coefficient of thermal conductivity

A = Area of the object

\Delta T =Temperature difference across object

d= thickness of object

According to the values given we have then,

k_{wool} = 0.04W/mK

\Delta T = 35.4-13.9

d = 1.87*10^{-3}m

A = 1.69m^2

Replacing we have,

\frac{Q}{t} = \frac{(0.04)(1.69)(35.4-13.9)}{1.87*10^{-3}}

\frac{Q}{t} = 777.21J/s

Therefore the quantity of heat per second does the person lose due to conduction is 777.21J/s

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<h3>What is resistance?</h3>

Resistance can be defined as the opposition to the flow of electric current in an electric circuit. The S.I unit of resistance is Ohms (Ω).

To calculate the resistance of the heater, we use the formula below.

<h3>Formula:</h3>
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From the question,

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Substitute these values into equation 1

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