Answer:
9.5X10^23 molecules N2 X (2 molecules NH3 / 1 molecule N2) = 1.9X10^24 molecules NH3
Explanation:
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The number of grams of Mgo that are produced is calculated as follows
calculate the moles of Mg used
that is moles =mass/molar mass
= 3.45 g/ 24.305g/mol = 0.142 moles
write the equation for reaction
that is 2 Mg + O2 = 2 MgO
by use of mole ratio between Mg to Mgo which is 2:2 this implies that the moles of Mgo is also 0.142 moles
mass of Mgo= moles x molar mass of MgO
molar mass of Mgo = 24.305 + ( 3x15.999) = 72.302 g/mol
mass= 0.142 mol x 72.302 g/mol= 10.27 grams
