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Fittoniya [83]
3 years ago
10

What will happen if a low massive main sequence star runs out of hydrogen fuel?​

Physics
1 answer:
babymother [125]3 years ago
4 0

Answer:

Low mass stars are: hydrogen burning in the core while on the Main Sequence. As the hydrogen fuel runs out, extreme pressure raises the temperature to 100 million degrees, where helium burning becomes possible.

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Which of the following can be a component of soil?
Evgen [1.6K]

Answer: what are the answers?

Explanation:

3 0
3 years ago
A 98.0 N grocery cart is pushed 12.0 m along an aisle by a shopper who exerts a constant horizontal force of 40.0 N. If all fric
Digiron [165]

Answer:

9.8 m/s

Explanation:

The work done by the force pushing the cart is equal to the kinetic energy gained by the cart:

W=K_f -K_i

where

W is the work done

K_f is the final kinetic energy of the cart

K_i is the initial kinetic energy of the cart, which is zero because the cart starts from rest, so we can write:

W=K_f

But the work is equal to the product between the pushing force F and the displacement, so

W=Fd=(40.0 N)(12.0 m)=480 J

So, the final kinetic energy of the cart is 480 J. The formula for the kinetic energy is

K_f=\frac{1}{2}mv^2 (1)

where m is the mass of the cart and v its final speed.

We can find the mass because we know the weight of the cart, 98.0 N:

m=\frac{F_g}{g}=\frac{98.0 N}{9.8 m/s^2}=10 kg

Therefore, we can now re-arrange eq.(1) to find the final speed of the cart:

v=\sqrt{\frac{2K_f}{m}}=\sqrt{\frac{2(480 J)}{10 kg}}=9.8 m/s



7 0
3 years ago
The dances created and performed collectively by the ordinary people.
Readme [11.4K]

Answer:

Folk dance

Explanation:

hope i helped :)

6 0
3 years ago
If an astronaut throws an object in space, the object's speed will _____________. A) decrease. B) increase. C) remain constant.
GenaCL600 [577]

The object's speed will remain constant after the it leaves his hand.

So will HIS speed in the opposite direction.

7 0
3 years ago
Read 2 more answers
A mystery element has three isotopes of the following masses and percent abundances: 93.597 amu at 23.63 % abundance, 96.191 amu
iogann1982 [59]

Answer:

92.397amu

Explanation: The exact amu of the mystery element is obtained by multiplying the relative abundance of each individual isotope by  its respective amu and then summing the results.

The sum of the total relative abundance for all the isotopes should be 100%.

However, the relative abundance of the isotope with 95.502amu is not given; therefore to obtain it we subtract the sum of the known relative abundances from 100% as follows:

Relative abundance of isotope with 95.502amu = 100-(23.63+30.53) = 42.84%

8 0
4 years ago
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