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Nimfa-mama [501]
3 years ago
5

An early submersible craft for deep-sea exploration was raised and lowered by a cable from a ship. When the craft was stationary

, the tension in the cable was 7000 N. When the craft was lowered or raised at a steady rate, the motion through the water added an 1800 N drag force.
(a) What was the tension in the cable when the craft was being lowered to the seafloor?
(b) What was the tension in the cable when the craft was being raised from the seafloor?
Physics
1 answer:
rusak2 [61]3 years ago
6 0

Answer:

a) 5200 N  b) 8800 N

Explanation:

a) tension in the cable when it was being lowered to the sea floor = weight of the object which acts downward ( equals the tension in the cable when the craft was stationary in opposite direction)  - the drag force which will act upward =  7000 - 1800 = 5200 N

b) tension in the cable when the craft was being raised since the tension will act upward and the drag force and the weight will act downward = 7000 + 1800 = 8800 N

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"In regards to the global energy budget, Earth absorbs ____________ wave radiation and emits ___________ wave radiation"
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Answer:

In regards to the global energy budget, Earth absorbs <u>short-</u><u>wave</u> radiation and emits <u>long-</u><u>wave</u> radiation.

Explanation:

It is required to tell what kind of wave radiation the earth absorbs and emits in regards to the global energy budget.

Let us discuss the global energy budget first.

The balance between the solar energy that enters Earth and the energy that leaves Earth and travels back into space is known as the global energy budget or the earth's energy budget. The visible region of the electromagnetic spectrum is where the majority of the sun's energy is found.

Therefore earth absorbs <u>short-</u><u>wave</u> radiation and emits <u>long-</u><u>wave </u>radiation in regard to the global energy budget.

To know more about, the global energy budget, refer to:

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Determine the energy required to accelerate an electron between each of the following speeds. (a) 0.500c to 0.900c MeV (b) 0.900
Aleonysh [2.5K]

Answer:

The energy required to accelerate an electron is 0.582 Mev and 0.350 Mev.

Explanation:

We know that,

Mass of electron m_{e}=9.11\times10^{-31}\ kg

Rest mass energy for electron = 0.511 Mev

(a). The energy required to accelerate an electron from 0.500c to 0.900c Mev

Using formula of rest,

E=\dfrac{E_{0}}{\sqrt{1-\dfrac{v_{f}^2}{c^2}}}-\dfrac{E_{0}}{\sqrt{1-\dfrac{v_{i}^2}{c^2}}}

E=\dfrac{0.511}{\sqrt{1-\dfrac{(0.900c)^2}{c^2}}}-\dfrac{0.511}{\sqrt{1-\dfrac{(0.500c)^2}{c^2}}}

E=0.582\ Mev

(b). The energy required to accelerate an electron from 0.900c to 0.942c Mev

Using formula of rest,

E=\dfrac{E_{0}}{\sqrt{1-\dfrac{v_{f}^2}{c^2}}}-\dfrac{E_{0}}{\sqrt{1-\dfrac{v_{i}^2}{c^2}}}

E=\dfrac{0.511}{\sqrt{1-\dfrac{(0.942c)^2}{c^2}}}-\dfrac{0.511}{\sqrt{1-\dfrac{(0.900c)^2}{c^2}}}

E=0.350\ Mev

Hence, The energy required to accelerate an electron is 0.582 Mev and 0.350 Mev.

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