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garri49 [273]
3 years ago
9

Determine the new pressure of a sample of hydrogen gas if the volume and moles are constant, the initial pressure is

Chemistry
1 answer:
masha68 [24]3 years ago
4 0

Answer:

6.3 atm

Explanation:

P2=T2P1/T1

Change C to K

We can check this by knowing that P and T at constant V have a proportional relationship; Hence, this is correct.

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If a mineral with a density of 6 g/cm3 is broken into 3, what is the density of each new piece?
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Answer:

If a mineral with a density of 6 g/cm3 is broken into 3, the density of each new piece is 6 \frac{g}{cm^{3} }

Explanation:

Density is a quantity that allows us to measure the amount of mass in a certain volume of a substance. In other words, density is the property that matter, whether solid, liquid or gas, has to compress into a given space, the amount of mass per unit volume.

As density is a physical property of matter that is defined as the ratio of an object's mass to its volume, each material or substance has its own density regardless of its size because the ratio between mass and volume is the same.

<u><em>If a mineral with a density of 6 g/cm3 is broken into 3, the density of each new piece is 6 </em></u>\frac{g}{cm^{3} }<u><em></em></u>

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3 years ago
Phosphorous pentchloride (pcl5 ) is used as a chlorinating reagent in chlorination of organic compounds. what type of bonding oc
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Plants produce a variety of substances:food,flavoring,drugs,poisons.this is a result of
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7 0
3 years ago
A container is filled with helium gas. It has a volume of 2.25 liters and contains 9.00 moles of helium. How many moles of heliu
Darina [25.2K]

Answer: There are 7.4 moles of helium gas present in a 1.85 liter container at the same temperature and pressure.

Explanation:

Given: V_{1} = 2.25 L,     n_{1} = 9.0 mol

V_{2} = 1.85 L,            n_{2} = ?

Formula used to calculate the moles of helium are as follows.

\frac{V_{1}}{n_{1}} = \frac{V_{2}}{n_{2}}\\

Substitute the values into above formula as follows.

\frac{V_{1}}{n_{1}} = \frac{V_{2}}{n_{2}}\\\frac{2.25 L}{9.0 mol} = \frac{1.85 L}{n_{2}}\\n_{2} = \frac{1.85 L \times 9.0 mol}{2.25 L}\\= 7.4 mol

Thus, we can conclude that there are 7.4 moles of helium gas present in a 1.85 liter container at the same temperature and pressure.

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