Ask question

Ask question

All categories

evablogger [386]

2 years ago

10

What is an example of potential energy to kinetic energy?

2 answers:

olga_2 [115]2 years ago

6 0

Potential energy is the store she energy from an object this could include rubber bands. Kinetic energy is the energy that deals with motion a good example is a person running

ValentinkaMS [17]2 years ago

5 0

Hello There!

Potential energy is energy that is stored in an object. Kinetic energy involves motion so an object that has potential energy turns into kinetic energy.

An example could be a roller coaster going up a hill and it's building potential energy so when it goes down the hill, the potential energy will turn into kinetic energy.

You might be interested in

You are working with a team to design a better electron microscope. To precisely control the beam of electrons, your team decide

rewona [7]

Answer and Explanation:

(a) The attached image below shows the diagram of a CRT in the helmholtz coils and well labelled with details

(b). The electron will follow a circular path which travels along under constant magnetic field

$r = \frac{mV}{qB}$

where m = mass of electron, V = velocity of electron, q = charge of the electron and B = magnetic field strength

4 0

2 years ago

Read 2 more answers

2. Use the diagram below to answer this question. As the ball moves from point A

Thepotemich [5.8K]

Answer:

at point A the ball possess pontetial energy , point B kinetic energy then point C pontetial energy

5 0

2 years ago

A 1.2 KG rubber ball is being thrown in the air if the ball is traveling at 2.0 M/S when it is 3.0 M off the ground what is the

Vitek1552 [10]

Answer:

37.7 J

Hope this helps! (see pictures)

6 0

2 years ago

What is the length of the orbit of the earth around the sun?

Rzqust [24]

Answer:

S = 2 π R

R (mean) = 92.9E6 miles

S = 2 * 3.14 * 92.9E6 miles = 5.84E8 miles

5 0

2 years ago

One wire carries a current of I1= 2 Amps, and the other carries a parallel current (same direction, wires are side by side) of I

Yuki888 [10]

Answer: $F=3\times 10^{-5} N$

Explanation:

Given

$I_1=2 Amps$

$I_2=0.75 Amps$

Length of each wires $\left ( L\right )=5 m$

Distance between wires $\left ( r\right )=5 cm$

Force per unit length = $\frac{\mu_0I_1I_2}{2\pi r}$

$F'=\frac{2\times 10^{-7}\times 2\times 0.75}{2\pi \times 0.05}$

$F'=6\times 10^{-6}$

Force for $L=5 m$

$F=3\times 10^{-5} N$

6 0

2 years ago